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nikitadnepr [17]
3 years ago
15

A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of

strength 0.3 tesla. What is the magnitude of the magnetic force on a 5m length of wire?​
Physics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

F=ILB sin \theta

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

\theta is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

L = 5 m

\theta=90^{\circ}

Substituting into the equation, we find

F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N

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