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blsea [12.9K]
3 years ago
5

What is the momentum of a 1550kg car that is traveling 38.0 m/s?

Physics
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

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Answer:

s = vcos(x)t

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cos(45)t = 2

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h = vsin(x)t + gt^2/2

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h = 10.8 metres

Explanation:

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Answer:

-10.8m/s^2

Explanation:

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An electron moves a 2.0x10^6 meter per the second perpendicular to a magnetic field having a flux density of 2 teslas. What is t
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Answer:

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Explanation:

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v: speed of the electron = 2.0*10^6 m/s

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However, the direction of B and v are perpendicular between them. So, the angle between vectors is 90°. The magnitude of the magnetic force is:

|F_B|=qvBsin90\°=qvB

You replace the values of q, v and B in the last equation:

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