What is the momentum of a 1550kg car that is traveling 38.0 m/s?
1 answer:
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Answer:
Explanation:
The electric field applies a force qE, but only in the y direction. This means that the x component of the
momentum must be conserved:
0 = Fx =dpx/dt
=⇒ px is conserved
pxi = γimvxi = pxf = γfmvxf (see the attactments)
the particle will acquire a velocity in the y
direction, and vxf <vxi. The x-component of the velocity, and thus the x-component of the momentum
must decrease.
