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kirza4 [7]
4 years ago
10

Which of the following does not involve colligative properties?

Chemistry
2 answers:
kumpel [21]4 years ago
8 0
The answer is d. calcium silicide is added to liquid steel to increase the steel's ability to freeze 
Dahasolnce [82]4 years ago
3 0

Answer:

B. Melting point acceleration

Explanation:

Educere/ Founder's Education

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Give four examples illustrating each of the following terms. a. homogeneous mixture b. heterogeneous mixture c. compound e. phys
zzz [600]

1. homogenous: sugar solution

2. heterogeneous: sand solution

3. compound: water

4. physical change: ice melting

5. element: hydrogen

6. chemical change: burning fire

6 0
3 years ago
A glass laboratory flask is filled with gas at 24 ∘C and 0.95 atm pressure, sealed, and then heated to 104 ∘C. What is the press
Elan Coil [88]

The pressure inside the flask on heating it is given as 1.21 atm.

<u>Explanation:</u>

As per Guy Lussac's law, the pressure of any concealed volume of gas particles will be directly proportional to the temperature of the container of the gas particles.

So P ∝ T

To convert celsius to kelvin, add 273.15 to the temperature value in celsius

Since, here the initial temperature of the flask is given as 24°C, so in kelvin it will be 297.15 K. Similarly, the final temperature is said to be 104°C which will be equal to 377.15 K. Then the final pressure will be increased as there is increase in temperature. So, the final pressure inside the flask can be obtained as

\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }

P_{2} = \frac{P_{1} }{T_{1} } \times T_{2} =\frac{0.95}{297.15} \times 377.15 =1.21\ atm

So, the pressure inside the flask on heating it is given as 1.21 atm.

3 0
4 years ago
How many kilocalories are needed to vaporize 5.8 mol of Br2
Valentin [98]
<span>The vaporization of br2 from liquid to gas state requires 7.4 k/cal /mol.</span>
8 0
3 years ago
Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
Read 2 more answers
Three clues that indicate chemical change <br>​
Bad White [126]

Explanation:

temperature

taste

and acidity rate

4 0
3 years ago
Read 2 more answers
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