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mart [117]
4 years ago
7

The teacher marked Silvano's problem wrong on his test.

Mathematics
1 answer:
mote1985 [20]4 years ago
7 0
I͟ h͟a͟v͟e͟ n͟o͟ i͟d͟e͟a͟ w͟h͟a͟t͟ h͟e͟ d͟i͟d͟ w͟r͟o͟n͟g͟ b͟e͟c͟a͟u͟s͟e͟ I͟ d͟o͟n͟'t͟ k͟n͟o͟w͟ t͟h͟e͟ o͟r͟i͟g͟i͟n͟a͟l͟ p͟r͟o͟b͟l͟e͟m͟.
B͟u͟t͟, f͟r͟o͟m͟ w͟h͟a͟t͟ I͟ c͟a͟n͟ s͟e͟e͟,

(4^5)^4= 4^5•4

=>4^20

W͟o͟u͟l͟d͟ b͟e͟ t͟h͟e͟ c͟o͟r͟r͟e͟c͟t͟ a͟n͟s͟w͟e͟r͟.

N͟o͟w͟, I͟ c͟a͟n͟ s͟e͟e͟ S͟i͟l͟v͟a͟n͟o͟ d͟o͟i͟n͟g͟ t͟h͟i͟s,

(4^5)^4=4^5+4

=>4^9

B͟u͟t͟, w͟h͟e͟n͟ a͟ p͟r͟o͟b͟l͟e͟m͟ i͟s͟ p͟u͟t͟ i͟n͟ p͟a͟r͟e͟n͟t͟h͟e͟s͟e͟s͟,
t͟h͟e͟n͟ r͟a͟i͟s͟e͟d͟ t͟o͟ t͟h͟e͟͟ p͟o͟w͟e͟r͟ o͟f͟ a͟ n͟u͟m͟b͟e͟r͟,
M͟U͟L͟T͟I͟P͟L͟Y͟ t͟h͟e͟ e͟x͟p͟o͟n͟e͟n͟t͟s͟ t͟o͟g͟e͟t͟h͟e͟r͟.


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Factor the expression<br> 20g3 + 24g2 – 15g – 18
abruzzese [7]
First, put parenthesis around the first two numbers and the last two numbers. 
(20g³+24g²) (-15g-18)
Then, take out the greatest common factor of both parenthesis. 
4g²(5g+6)-3(5g+6)
You then separate the numbers outside the parenthesis and the numbers in the parenthesis. 
(5g+6) (4g²-3) 
Then you simplify the second set of numbers. Since the set of numbers can't be simplified, you would leave this problem as it is. I hope this makes sense.
3 0
3 years ago
Please help, will give brainliest to first
Lelechka [254]

Answer:

AN = 16 units

Step-by-step explanation:

So we can use the fact that \frac{AN}{FN} =\frac{OR}{FR}

  • Since this is an isosceles triangle, segments FO and FR are both equal to 7

Manipulating the equation above to solve for AN we have AN = \frac{(FN)(OR)}{FR}

  • Substituting in the known values we have AN=\frac{(10)(11.2)}{7} =16

8 0
3 years ago
Read 2 more answers
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
Rotate the rectangle 90∘ clockwise about the cross
netineya [11]

Answer:

\large \boxed{\mathrm{view \ attachment}}

Step-by-step explanation:

The rectangle is rotated 90 degrees clockwise about the cross.

8 0
3 years ago
F. Please answer this as soon as possible.
Liono4ka [1.6K]

Answer:

-12

Step-by-step explanation:

Convert the mixed number to an improper fraction.

-2\frac{2}{3} = -\frac{8}{3}

To divide, just multiply by the reciprocal.

So -2\frac{2}{3} ÷ \frac{2}{9} becomes -\frac{8}{3} ÷

Now you can multiply straight across.

-\frac{8}{3} × \frac{9}{2} = -\frac{72}{6}

And simplify.

-\frac{72}{6} = -12

Please mark as Brainliest! :)

7 0
3 years ago
Read 2 more answers
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