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3 years ago

11

Type the correct answer in each box. Use numerals instead of words.

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

$(4,-3)$ and $(-2,5)$

Step-by-step explanation:

It was given that the points $(-3,4)$ and $(5,-2)$ are on the graph of the function $f$ .

If $g$ is the inverse function of $f$ , then $g$ will take the y-values as inputs and give the x-values as outputs.

Hence we will have the ordered pairs $(4,-3)$ and $(-2,5)$

on g.

In other words, f and g are symmetric about the line $y=x$ . This implies that when we reflect the points $(-3,4)$ and $(5,-2)$ in the line $y=x$ we will obtain $(4,-3)$ and $(-2,5)$ .

This point must lie on g.

dolphi86 [110]3 years ago

6 0

Answer:

(4,-3) and (-2,5)

Step-by-step explanation:

I got it right.

You might be interested in

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

What is 0.7 in simplest form

dolphi86 [110]

7/10 you can not simplify tht fraction any more. 7 does not go into
10 evenly.

7 0

3 years ago

Jaime wants to know how fast she can type, so she times herself as she types a paper. The paper has 429 words in it, and Jaime t

vitfil [10]

Her typing rate is 33words per minute

3 0

3 years ago

Square root of 486x^2

Leona [35]

This is a perfect Square

486 x 486 = 236,196

5 0

3 years ago

12x+2=146 what does X equal

LiRa [457]

Answer:

x = 12

Step-by-step explanation:

12x = 146 - 2

x = 144 ÷ 12

x = 12

4 0

4 years ago