Answer:
7 hours
Step-by-step explanation:
Answer:
The distance between P and Q is 54
Step-by-step explanation:
We are given that triangle RPQ is similar to triangle RTS.
Property of similar triangle: The ratio of any pair of corresponding sides is the same.
So, by property :
PR=42
PQ=x
ST=36
RT=28
So,
54=x
Hence the distance between P and Q is 54
<span>rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8
so
</span><span>Diagonals PR = QS
if PR = 22.8 then QS = 22.8
TQ = QS/2 = 22.8 / 2 = 11.4
anser
TQ = 11.4</span>
Y= 3x + 1
If x is 2 we plug in 2 instead of x
The equation becomes y= 3(2) + 1
now you just solve
y= 6+1
y=7
Answer:
x² - 10x + 21 = 0
Explanation:
The standard form of the quadratic equation is:
ax² + bx + c = 0
This means that we want to have all terms on one side and a zero on the other.
This can be done as follows:
x² - 10x + 16 = -5
Add 5 to both sides of the equation:
x² - 10x + 16 + 5 = -5 + 5
x² - 10x + 16 + 5 = 0
Combine like terms to get the final expression in standard form as follows:
x² - 10x + 21 = 0
Hope this helps :)