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Sergeeva-Olga [200]
3 years ago
5

he volume required to reach the equivalence point of an acid-base titration depends on the volume and concentration of the acid

or base to be titrated and on the concentration of the acid or base used to do the titration. It does not, however, depend on the whether or not the acid or base being titrated is strong or weak. Explain.
Chemistry
1 answer:
solong [7]3 years ago
7 0

Answer:

the equivalence point occurs when the amount of added titrating substance is stoichiometrically equivalent to the present amount of the analyte or substance to be analyzed in the sample

Explanation:

in the equivalence point,  we have:

  • moles of acid = moles of base

⇒ (Volume * Concentration )acid = (Volume * Concentration)base

As can be seen in the equation, at the point of quivalence there is complete salt formation, so the pH is calculated through the salt, therefore, it is not significant how strong or weak the base or acid is in the titration.

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What element has an atomic mass 4?
Daniel [21]

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

4 0
3 years ago
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4. How many moles are in 54.0 grams of Silver?
sineoko [7]
4. Molar mass of silver m Ms~=108 g/mol
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5. 6.3*(108/1)=680.4g

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6.0*(6.022*10^23/1)=36.132*10^23 atoms

7. Molar mass of Krypton : Mk=84 g/mol
112/84=1.33 moles of Kr

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9. Molar mass of Silicon : Ms=28 g/mol
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7 0
3 years ago
3 NO2(g) + H2O(ℓ) −→
gulaghasi [49]
The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
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volume of NO formed - 285 L
7 0
3 years ago
A chemist prepares a solution of sodium thiosulfate (Na2S203) by measuring out 110.g of sodium thiosulfate into a 350. mL volume
forsale [732]

Answer:

1.99 M

Explanation:

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The volume of solution is 350 mL = 0.350 L.

The molarity of sodium thiosulfate is:

M = moles of solute / liters of solution

M = 0.696 mol / 0.350 L

M = 1.99 M

5 0
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Pls help 6th grade science
lys-0071 [83]

Answer:

C.)

Explanation:

I also saw this question on Brainly! Hope this helps!

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