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Sergeeva-Olga [200]
3 years ago
5

he volume required to reach the equivalence point of an acid-base titration depends on the volume and concentration of the acid

or base to be titrated and on the concentration of the acid or base used to do the titration. It does not, however, depend on the whether or not the acid or base being titrated is strong or weak. Explain.
Chemistry
1 answer:
solong [7]3 years ago
7 0

Answer:

the equivalence point occurs when the amount of added titrating substance is stoichiometrically equivalent to the present amount of the analyte or substance to be analyzed in the sample

Explanation:

in the equivalence point,  we have:

  • moles of acid = moles of base

⇒ (Volume * Concentration )acid = (Volume * Concentration)base

As can be seen in the equation, at the point of quivalence there is complete salt formation, so the pH is calculated through the salt, therefore, it is not significant how strong or weak the base or acid is in the titration.

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Determine the oxidation state of the metal ion in [co(nh3)5br]2+. express your answer as an integer.
Zanzabum
                                           [Co(NH₃)₅Br]²⁺

Ligands and charges on them,

                             5 × NH₃  =  5 × 0  =  0

                             1 × Br⁻¹  =  1 × -1  =  -1

Charge on sphere  =  +2

So, putting values in equation,

                                       Co + (0)₅ - 1  =  +2

                                       Co + 0 - 1  =  +2

                                       Co - 1  =  +2

                                       Co  =  +2 + 1

                                       Co  =  +3

Result:
           Oxidation state of Co in [Co(NH₃)₅Br]²⁺ is +3.
7 0
3 years ago
Write down the formula for B<br> example:<br> Hydrogen + Fluorine = Hydrogen Fluorine <br><br> help
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Answer:

P³⁻ + Cl⁻ --> PCl₃

Explanation:

PCl₃: phosphorus trichloride. prefix in front of chloride is "tri"–meaning three.

5 0
3 years ago
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Is mixing sodium and water a physical or a chemical change
adoni [48]

Answer:

physical

Explanation:

3 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

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3 years ago
What is the value of Kw at 25°C?<br> 1.0 x 10–14 <br> 1.0 x 10–7<br> 1<br> 7<br> 14
romanna [79]
<span>1.0 x 10-14. That is the value of Kw at 25 degrees C.


</span>
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3 years ago
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