The answer is
6.8 * 10^-15
The explanation:
1- we have to convert all measurements to the same units:
Conversions:
when 1 m = 100 cm
and 1 m = 10^12 pm
So,
proton radius: 1.0*10^-13 cm * (1m / 100 cm) = 10^-15 m
proton volume: 4/3 * pi * r^3 = 4/3 * pi * (10^-15 m)^3 = 4.2 * 10^-45 cu. meters
and
H atom radius: 52.9 pm * (1m / 10^12 pm) = 5.29 * 10^-11 m
H atom volume: 4/3 * pi * r^3 = 4/3 * pi * (5.29 * 10^-11 m)^3 = 6.2 × 10^-31 cu. meters
So,
2- Fraction of space occupied by nucleus = proton volume / H atom volume
= (4.2 * 10^-45 cu. meters) / (6.2 × 10^-31 cu. meters)
= 6.8 * 10^-15
So, the "fraction" would be 6.8 * 10^-15 out of 1.
The answer is D. just like the other guy said...
Rutherford's model didn't not account for the properties of electrons. bohr placed electrons in layers of orbit so C
Answer:
The following three isomeric structure are given below.
Explanation:
Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂
Ester #1: methyl 1-methylcyclobutanecarboxylate
Ester #2: (E)-methyl 3-methyl-3-pentenoate
Ester #3: isopropyl 2-methylpropenoate
