Answer:
CH4 +O2 => CO2 + 2 H2O
None were in excess
Explanation:
Equation for the reaction is,
CH4 + O2 =>CO2 +2 H2O
No of moles of CH4 = (20 /1000)/24 =0.02 /24 = 0.00083
No of moles of O2 =20 /24000 = 0.0083
CH4 : O2 = 1:1
THEREFORE
None of the gases were in excess.
D.no as conflict were not considered
Answer:
27 g
Explanation:
M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol
100 mL = 0.1 L solution
1.5 M = 1.5 mol/L
1.5 mol/L * 0.1 L = 0.15 mol C6H12O6
0.15 mol * 180 g/1 mol = 27 g C6H12O6
Answer:
0.693 (you can round it up if you want to)
Explanation:
Density= mass ÷ volume
54.2 ÷ 78.1 = 0.693
I hope this helped☺
Answer:
NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.
Explanation:
