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nirvana33 [79]
3 years ago
10

Why do we use the mole concept ??

Chemistry
2 answers:
Kaylis [27]3 years ago
7 0

Answer:

Here

Explanation:

Chemists need the mole concept to bridge the gap between the microscopic world of atoms to the macroscopic world of humans. As you know, the molecular level consists of particles that are invisible to us.

uysha [10]3 years ago
6 0

Answer:

it allows us to count atoms and molecules by weighing macroscopic amounts of material.

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What is true of dynamic equilibrium?
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Answer:

Dynamic equilibrium is a state in which reactant is converted into products at the same rate. At the beginning of a reaction, the reactants are converted to products and reaction goes into forwarding direction.

But in reversible reaction products start changing into reactants and reaction goes in the reverse direction until an equilibrium is reached. The state where the rates of all the reactants and products become equal and no more changes take place except the concentration is called dynamic equilibrium.

All the changes in dynamic equilibrium cancel out each other and the system seems to be at equilibrium.

7 0
3 years ago
I need help with this i'm really dumb.<br> Balance<br> p4+o2 ----&gt; p4o10
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Answer:

P4 + 5O2 → P4O10

Explanation:

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4 years ago
find the total pressure of a gas that initially occupied 27 L at 32 degrees Celsius and 2.5 atm, if the final conditions are 12
yawa3891 [41]

Answer: Total pressure of the gas will be 0.716atm.

Explanation: We are given a gas having initial conditions as

V = 27L

T = 32°C = 305K

P = 2.5atm

As the gas remains same, number of moles of a gas will also be same for initial and final conditions. To calculate the number of moles, we use ideal gas equation, which is,

                                              PV=nRT                  .......(1)

where, R = gas constant = \text{0.08206 L atm }mol^{-1} K^{-1}

For calculating number of moles:

                          n=\frac{PV}{RT}

Putting the values of initial condition in this equation, we get

n=\frac{(2.5atm)(27L)}{\text{(0.08206 L atm }mol^{-1} K^{-1})(305K)}

n = 2.696 mol

Now, the final conditions are,

V = 88.0L

T = 12°C = 285K

n = 2.696 mol (calculated above)

P = ? atm

Again using equation 1, we get

                                 P=\frac{nRT}{V}

P=\frac{(2.696mol)(\text{0.08206 L atm }mol^{-1} K^{-1})(285K)}{88.0L}

P = 0.716atm.

7 0
3 years ago
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