X=-2→y=7(6)^(-2+2)+1=7(6)^0+1=7(1)+1=7+1→y=8; (x,y)=(-2,8)
x=-5→y=7(6)^(-5+2)+1=7(6)^(-3)+1=7/6^3+1=7/216+1=0.0324+1→y=1.0324→(x,y)=(-5,1.0324)

Answer: Graph 3

3 0

3 years ago

find an equation for the nth term of a geometric sequence where the second and fifth terms are -8 and 512

kaheart [24]

Answer:

$n_x = -4n_{x-1}\\$

where $n_1$ = 2

Step-by-step explanation:

512/-8 = -64

difference of n = 3

$\sqrt[3]{64} = 4$

$n_x = -4n_{x-1}\\$

where $n_1$ = 2

7 0

3 years ago

1.) Which function in vertex form is equivalent to f(x) = x2 + x +1?

Gwar [14]

Hello,

Answer C

x²+x+1=(x²+2*1/2*x+1/4)+1-1/4=(x+1/2)²+3/4

5 0

3 years ago

2x+3y + 2z = 05x – 3y +4=17x+9y-4z=11​

2x+3y + 2z = 05x – 3y +4=17x+9y-4z=11