Step-by-step explanation:
so we're making two draws *with* replacement (this is important)
step 1: for the first draw, it wants the probability of getting a sour candy. to calculate this:
(# of sour candy) / (total # of candy)
step 2: for the second draw, it wants the probability of *not* getting a sour candy. to calculate this, you can calculate 1 - (the probability form part 1).
step 3: to find the probability of both events happening together, simply multiply the probabilities from part 1 and 2 together
side note: for step 2, you can only do this because the candy is being replaced. if there were no replacement, you'd have to re-calculate (# of non-sour candies) / (total after the first candy is drawn)
Answer:
i don't now ugly
Step-by-step explanation:
Answer: 701953087225 is the answer
Answer:Gary made 15 baskets.
Susan made 10 baskets.
Bill made 17 baskets.
Step-by-step explanation:
Let x represent the number of baskets that Gary made.
Let y represent the number of baskets that Susan made.
Let z represent the number of baskets that Bill made.
Gary made 5 baskets than Susan this season. This means that
x = y + 5
Bill made 3 less than twice as many baskets as Susan. This means that
z = 2y - 3
Together, all three made 42 baskets. This means that
x + y + z = 42 - - - - - - - - - - 1
Substituting x = y + 5 and z = 2y - 3 into equation 1, it becomes
y + 5 + y + 2y - 3 = 42
4y + 2 = 42
4y = 42 - 2 = 40
y = 40/4 = 10
x = y + 5 = 10 + 5
x = 15
z = 2y - 3 = 2 × 10 - 3
z = 20 - 3 = 17
