Answer:
x = -4 ;
Step-by-step explanation:
6(x+3)=2(2x+5)
Distribution
6x+18 = 4x + 10
Subtract 4x on both sides
2x+18 = 10
Subtract 18 on both sides
2x = -8
Divided by 2
x = -4
Now if we have to substitute the value of X
6(-4+3)=2(-8+5)
Parenthesis first
6(-1) = 2(-3)
-6 = -6
Simple,
you have a fixed rate of $25, meaning you get a haircut, it's $25
ANY other service is an extra $15
So, let's make the equation...
y=15x+25
Now, to just get a haircut it's $25.
But, let's say you get a haircut+shampoo
It'd be..
y=15(1)+25
y=$40
Another one..
You get a haircut+shampoo+highlight
y=15(3)+25
y=$70
And so on, and so forth.
I know you said 2 numbers but here is a list :)
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88
Answer: provided in the explanation segment
Step-by-step explanation:
here i will give a step by step analysis of the question;
A: Optimization Formulation
given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5
Objective function: Minimize manufacturing cost (Z)
Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33
s.t
X11 + X12 + X13 + X14 + X15 = 600
X21 + X22 + X23 + X24 + X25 = 1000
X31 + X32 + X33 = 800
X11 + X21 + X31 <= 400
X12 + X22 + X32 <= 600
X13 + X23 + X33 <= 400
X14 + X24 <= 600
X15 + X25 <= 1000
Xij >= 0 for all i,j
B:
Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.
cheers i hope this helps!!