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LenaWriter [7]
3 years ago
9

Julie is selling candy bars to raise money for new band uniforms. Candy bar x sells for $2 and candy bar y sells for $3. The num

ber of y candy bars Julia sells must be greater than or equal to three times the number of x candy bars she sells. She has at most 36 candy bars to sell. What is the maximum revenue she can make?

Mathematics
2 answers:
GalinKa [24]3 years ago
7 0
In this question, you are asked how much the maximum revenue. Since candy Y sold for a higher price than candy X, that means you have to sell candy Y as much as possible.
The number of candy Y must be >= 3 times candy X. Since this won't limit candy Y selling, then you can convert all 36 candy into candy Y and 0 candy X

36 candy (Y) >= 0 candy(X) ----> the requirement is met.

<span>The revenue would be 36 candy Y * $3/candy Y= $108</span>
sukhopar [10]3 years ago
3 0

Answer:

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