Answer:
distance traveled by 3 second ball ≈ 45m
distance traveled by 1 second ball ≈ 5m
Explanation:
Since the 2 balls started at rest, their v initial = 0, and since no other force is acting on them except for the gravitational force, they accelerate downwards at 10m/s2.
To calculate the distance traveled by both balls, we apply the second formula of UARM motion:
• Δx = 1/2(a)(t^2) + (v0)(t)
Applying both 1s and 3s in this formula will yield you 5m and 45m respectively.
Hope this helps, brainliest would be appreciated :)
Answer:
Question (a)
• We shall use masses of 200g, 50g, 20g and 5g.
Question (b)
• We shall use masses of 500g, 200g, 50g, 20g and 5g.
Answer:
Part A:
Part B:
Explanation:
Part A:
We should determine the free-body diagram of the small box.
For the first box, the only force exerted to the box is the static friction force in the direction of the motion.
(The direction of the static friction is always confusing to the students. The wrong idea is that the static friction is in the opposite direction with the motion. However, if you look at the Newton's Second Law, it states that the net force acting on an object is equal to the mass times acceleration. And in this case acceleration of the total system is equal to that of the small box, since it sits on the larger box.)
We can use the equations of kinematics to find the minimum distance to stop without the small box slipping.
The acceleration can be found by Newton's Second Law:
The negative sign comes from the fact that in order for the boxes to stop they have to apply a negative acceleration.
Now, we can combine the two equations to find the distance x:
Part B:
We can apply the above formula to the truck and file cabinet.
Answer:
t = 2.26 10⁵ s
Explanation:
Let's calculate the flow of water that comes out of the hose
Q = A v
The area of a circle is
A = π r²
Q = π r² v
Let's reduce the units to the SI system
d = 5/8 in (2.54 10⁻² m / in) = 1.5875 10⁻² m
r = d / 2 = 0.79375 10⁻² m
Q = π (0.79375 10⁻²)² 0.59
Q = 1.1678 10⁻⁴ m³ / s
Let's calculate the volume of the pool
V = π R² h
V = π (4.6 / 2)² 1.6
V = 26.59 m³
Let's use a rule of proportions (rule of three), to find the time
t = 26.59 (1 / 1.1678 10⁻⁴)
t = 22.77 10⁴ s
t = 2.26 10⁵ s
Answer: 2mph
Explanation:
In relative vector : Considering objects A and B
a) when two objects are moving in the same direction
Vab = Va + Vb
b) when two objects are moving in an opposite direction
Van = Va - Vb
Hence, this rule will be applied.
Speed upstream = ( 33-v ) opposite direction of the current
Downstream = ( 33+v ) same direction with the current
Distance = speed × time
Time upstream = 35/60
Time downstream = 31/60
From the formulae distance = speed × time
Upstream = ( 33-v ) × 35/60 ............ 1
Downstream = ( 33+V ) × 31/60 .............. 2
Equate 1 and 2
33-v) ×35/60 = 33+V) ×31/60
Multiply both side by 60
1155-35v = 1023+31v
1155-1023 = 31+35
132 = 66v
V = 2mph