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Alja [10]
3 years ago
15

Slow response times by paramedics, firefighters, and policemen can have serious consequences for accident victims. In the case o

f life-threatening injuries, victims generally need medical attention within 8 minutes of the accident. Several cities have begun to monitor emergency response times. In one such city, the mean response time to all accidents involving life-threatening injuries last year was m = 6.7 minutes. Emergency personnel arrived within 8 minutes on 78% of all calls involving life-threatening injuries last year. The city manager shares this information and encourages these first responders to do better. At the end of the year, the city manager selects an SRS of 400 calls involving life-threatening injuries and examines the response times. Awful accidents (a) State hypotheses for a significance test to determine whether first responders are arriving within 8 minutes of the call more often. Be sure to define the parameter of interest. (b) Describe a Type I error and a Type II error in this setting and explain the consequences of each. (c) Which is more serious in this setting: a Type I error or a Type II error? Justify your answer.
Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

a)

H_0: \pi\geq0.78\\\\H_a: \pi

b) The Type I error occurs when we reject a null hypothesis that is actually true. In this case, it means we conclude that the arrival time have improved, when it didn't.

The Type II error occurs when we accept a null hypothesis that is actually false. In this case, although the arrival times have really improved, the evidence from the sample was not enough to show that improvement.

c) In this case, the Type I error is more serious, because it gives the wrong impression of improvement and no further actions will be taken to reduce the times.

Step-by-step explanation:

a) If you want to determine if the responders are arriving within 8 minutes of the call more often, you have to evaluate the proportion of accidents in which the arrival time is less than 8 minutes and compare it with the known proportion of π=0.78.

The sample parameter "p: proportion of accidents with arrival time of 8 minutes or less" will be used to test the hypothesis.

The null and alternative hypothesis will be:

H_0: \pi\geq0.78\\\\H_a: \pi

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Ne4ueva [31]
1. Pi is usually referred to as 3.14, so the answer is 1

2. b) Endless

3. d) √5

4. a) 1/27

5. c) Irrational Numbers

I hope this helps! Let me know if you would like an explanation as to how I got the answers :)
5 0
3 years ago
F(x) = 2/x, g(x) = |x| -1 <br><br> what is the domain of (fog) (x)?<br><br> WILL MARK BRAINLIEST
DIA [1.3K]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

5 0
3 years ago
The percent amounts of sand in 5 soil samples from the same garden are 73%, 68%, 88%, 74%, 81%. What is the average percent of s
alina1380 [7]
0.73+0.68+0.88+0.74+0.81=3.84

3.84 divided by 5
=0.768x100
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3 0
3 years ago
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Studentka2010 [4]

Answer:

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A line code is a code used to transmit digital signal data over a transmission line. Common line encodings are unipolar, polar, bipolar, and Manchester code. NonReturn-to-Zero NRZ and Return-to-Zero technologies are used in unipolar, polar, and bipolar line coding schemes. Line coding is used to reduce bandwidth, reduce the chance of error, and increase efficiency. The purpose of this lab is to understand different types of row encoding, use MATLAB to implement row encoding functions, and use the input data to simulate those row encoding functions.

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5 0
2 years ago
Select the correct answer from each drop-down menu. B For circle O, m In the figure, 2 C CD T - 125° and m2ABC= 55°. and 2 have
Veronika [31]

Answer:

Step-by-step explanation:

The relevant relations here are ...

  • the sum of arc measures in a semicircle is 180°
  • the sum of angles in a triangle is 180°

<h3>Arc measures</h3>

The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:

  arc DA = 180° -CD = 180° -125° = 55°

Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.

 ∠ABO = 90° -∠AOB = 90° -55°

  ∠ABO = 35°

<h3>Triangle angles</h3>

In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.

  ∠ACB = 90° -∠ABC = 90° -55°

  ∠ACB = 35°

In the figure, angles ABO and ACB have measures of 35°.

6 0
2 years ago
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