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Sav [38]
3 years ago
12

Can someone help me with this question please?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

the answer will be 4/3 in slope form

Step-by-step explanation:

the answer will be 4/3 in slope form

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What is 7 8/13 rounded to the nearest whole number?
vfiekz [6]

Answer: The answer would be 8.

Step-by-step explanation: I'm going to assume you mean 7 8/13 is a mixed fraction. So you multiply the denominator, 13, multiply 7 to that, then add 8 to it and the denominator would be the same as before. That should give you 99/13. When you divide, you get around 7.6, rounding closest to 8.  

6 0
2 years ago
What numbers can be rounded to 360 when rounded to the nearest ten
mestny [16]
355, and any greater number that's less than 365, can.
4 0
2 years ago
Read 2 more answers
Using formula z equals x over 5 and solving for x which is correct? x equals 5 z or x equals 5 over x or x equals z over 5 or x
erastovalidia [21]
Original
Z = X/5
Solve for X
Multiply both sides by 5
5Z = X
Answer
X = 5Z
6 0
3 years ago
Solve the following system: <br> 3x + 2y = 7 <br> -4.5x - 3y = -10.5
valentina_108 [34]

Answer:

<u>infinitely many solutions</u>

Step-by-step explanation:

The system of equations :

  1. 3x + 2y = 7
  2. -4.5x - 3y = -10.5

Multiplying Equation 1 times 3 and Equation 2 times 2 :

  • 9x + 6y = 21
  • -9x - 6y = -21

Putting the equations in standard form after simplifying :

  1. 6y = -9x + 21 ⇒ <u>y = -1.5x + 3.5</u>
  2. -6y = 9x - 21 ⇒ <u>y = -1.5x + 3.5</u>

<u />

As both equations are the same, the system will have <u>infinitely many solutions</u>.

4 0
1 year ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
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