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Lady bird [3.3K]
3 years ago
13

Two boats are observed by a parasailer 75 meters above a lake. The angles of depression are 12.5° and 79. How far apart are the

boats?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

The two boats are 323.72 m apart.

Step-by-step explanation:

See the attached diagram.

B is the point of observation and AB is the height of the parasailer i.e. 75 m.

Now, from the right triangle Δ ABC,

\tan 79^{\circ} = \frac{AB}{AC} = \frac{75}{AC}

⇒ AC = 14.58 meters.

Again, from the right triangle Δ ABD,

\tan 12.5^{\circ} = \frac{AB}{AD} = \frac{75}{AD}

⇒ AD = 338.30 meters.

Hence, CD = AD - AC = 338.30 - 14.58 = 323.72 m

Therefore, the two boats are 323.72 m apart. (Answer)

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To find the product of

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First we expand the bracket ,

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Hence

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3 years ago
Which shows 0.124 in expanded form? A. ( 1 × 1 10 ) + ( 2 × 1 100 ) + ( 4 × 1 1000 ) B. 1 + ( 2 × 1 100 ) + ( 4 × 1 1000 ) C. 1
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Answer:

A. ( 1 × 1 / 10 ) + ( 2 × 1 / 100 ) + ( 4 × 1 / 1000 )

Step-by-step explanation:

A number is written in expanded form if it shows the sum of the values of the individual digits that make up the number.

To write 0.124 in expanded form, follow these steps:

<em>(i) Take the digits one after the other and multiply it by its value depending on its place. </em>

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The value is 0 unit, where a unit is 1

<em>Now multiply 0 by 1</em>

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<em>Now multiply 1 by 1 / 10</em>

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The value is 2 hundredth, where a hundredth is 1 / 100

<em>Now multiply 2 by 1 / 100</em>

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<em>Taking the fourth digit </em>- 4

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