<span>integral of (e^3x)/((e^6x)+1) dx = (e^6 x - log(e^6 x + 1))/e^9 + c</span>
Answer:
20, -7, -14, 10, -5, 8
20 + 10 + 8 + (-5) + (-7) + (-14) - organize all values (makes it easier to add)
38 + (-26) - add like terms
12
12/6 -divide sum by number of values
2 - answer
hopes this helps
Step-by-step explanation:
Answer:
Half a pound.
Step-by-step explanation:
To find the number of pounds he ate, multiply the fractions.
He ate 1/2 a pound.
Step-by-step explanation:
just put the ratios into a fraction if x:y then x/y
A.)6/1=6
B.)12/2=6
C.)4/24=1/6
D.)48/8=6
E.)18/3=6
F.)1/6
24/4=6 so A, B, D, and E are equivilant to the ratio 24/4
Hope that helps :)
25.12 if this is wrong I’m sorry