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3 years ago

What is the product? 2х(х – 4)

Mathematics

1 answer:

Otrada [13]3 years ago

3 0

2x2-8x (two x squared minus 8 x)

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If a aquadrilateral is equiangular, then it coul be a .....

kupik [55]

Answer:

Square

Answer A is correct

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3 years ago

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The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any meth

Lubov Fominskaja [6]

Answer:

$\frac{128\pi}{3}$ cubic units

Step-by-step explanation:

We are given that a region bounded by a curves $x=(y-7)^2$

x=4 and about y=5

We have to find the value of volume of the resulting solid

To find the volume of resulting solid we are using cylinder method

Substitute the values of x then we get

$(y-7)^2=4$

$y-7=\pm2$

y-7=2 and y-7=-2

y=7+2=9 and y=-2+7=5

Radius of cylinder =r=y-5

and height =h= $4-(y-7)^2=4-y^2-49+14 y=-y^2+14 y -45$

Using cylinder method and integrate along y -axis from y=5 to y=9

Volume = $\int_{a}^{b}2\pi r h dy=\int_{5}^{9}2\pi(y-5)(-y^2+14 y -45) dy$

volume= $2\pi\int_{5}^{9}(-y^3+19y^2-115y+225)dy$

Volume = $2\pi[-\frac{y^4}{4}+19\frac{y^3}{3}-115\frac{y^2}{2}+225y]^9_5$

Volume = $2\pi[-\frac{6561}{4}+\frac{625}{4}+19(\frac{729-125}{3})-115(\frac{81-25}{2})+225(9-5)]$

Volume= $2\pi(-1484+\frac{11476}{3}-3220+900)$

Volume = $2\pi(\frac{11476}{3}-3804)$

Volume = $2\pi(\frac{11476-11412}{3})=\frac{128\pi}{3}$

Hence, volume of resulting solid = $\frac{128\pi}{3}$ cubic units

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3 years ago

What is 1 8/9 written as a improperfraction

Yakvenalex [24]

To write this as an improper fraction you would multiply 9 by 1 then add your product to the numerator.
9x1=9
9+8=17
17/9
Hoped this helped!

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3 years ago

Which statement is true regarding the graphed functions?

Zigmanuir [339]

Answer:

the answer to your question is f(2)=0 and g(-2)=0

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3 years ago

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The steps to solving the expression the quantity of the sum of three squared plus four divided by the absolute value of negative

bearhunter [10]

Answer:

Step 3 should be ((9+4)/(0.25))-10.4 divided 4

Step 6 should be 52 - 2.6

I got it right on my exam :)

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1 year ago