Volume of the cone = 1/3 π r² h
Volume of the cone = 1/3 π (300÷2)² (150) = 3, 534,291.74 m³
Answer: 3, 534,291.74 m³
Answer:
40yd
Step-by-step explanation:
area of total minus unshaded portion
Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS
The answer is D
alternate interior angles <span />
Answer:
-0.04
Step-by-step explanation:
4.23-5= -0.77
-0.77*0.04= -0.03
-0.77*0.09= -0.07
-0.07 + -0.03= -0.04
