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3 years ago

What is the value x in the right triangle

Mathematics

2 answers:

polet [3.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

7 squared + 5 squared

svp [43]3 years ago

3 0

Answer:

D) 2*(sqrt)6

Step-by-step explanation:

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A(-1,2) B(3,1) C(1,-4) To the new coordinated A'(-2,4) B'(6,2) C'(2,-8) what was the scale factor?

kicyunya [14]

Answer:

Step-by-step explanation:

A(-1, 2) ==> A'(-2, 4)

B(3,1) ==> B'(6,2)

C(1,-4) ==> C'(2,-8)

Based on the results of each set, the scale factor is 2

A(-1*2, 2*2)= A'(-2, 4)

6 0

3 years ago

3D In the cryptarithm shown, different letters stand for different digits, and no leading digit can equal 0. Find the greatest p

svp [43]

Answer:

1961

Step-by-step explanation:

The greatest value of OFF can be achieved by making the hundreds places the greatest, followed by the tens, and then the ones.

S=9

A=8

U=7

T=6

N=5

986+975=1961

7 0

3 years ago

Read 2 more answers

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.

$y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7$

Substitute these into the ODE to see everything checks out:

$2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14$

5 0

3 years ago

Find the sum or difference. 1 3/10 + 2 2/5

pychu [463]

The answer is 3 7/10

8 0

3 years ago

Read 2 more answers

Does anyone know how to do this?

docker41 [41]

Answer:

bone or necklace

Step-by-step explanation:

3 0

3 years ago