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Setler79 [48]
4 years ago
14

Each time the heart beats,what does it do to blood

Physics
1 answer:
IgorC [24]4 years ago
4 0
The blood then carries oxygeb around the body which this helps us to breath around the body this process happens again
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Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth
Solnce55 [7]

Answer:

Force between two identical conducting ball will be 2.65\times 10^{-5}N                        

Explanation:

We have given there is two identical conducting small spheres having charge q_1=12nC=12\times 10^{-9}C and q_2=-21nC=-21\times 10^{-9}C

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}

So force F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N

So force between two identical conducting ball will be 2.65\times 10^{-5}N

4 0
3 years ago
Ilya and Anya each can run at a speed of 8.90mph and walk at a speed of 3.80mph . They set off together on a route of length 5.0
jekas [21]

Answer:

a) t = 56.34 minutes

b) v = 5.32mph

c) t = 47.22 minutes

d) v = 6.35 mph

Explanation:

Given;

The speed of Ilya and Anya are

Run = 8.90mph

Walk = 3.80mph

distance = 5.00 miles

a) anya walk half the distance and run half the distance.

Speed = distance/time

time = distance/speed

t1 = 5×0.5/3.80 = 0.658hr

t2 = 5×0.5/8.90 = 0.281hr

t = t1 + t2 = 0.658+0.281 = 0.939hr × 60minutes/hr

t = 56.34 minutes

b) average speed = total distance/total time taken

v = 5.00miles/0.939hr = 5.32mph

c) Ilya walk half the time and run half the time.

t1 = t2 = t/2

Distance = speed × time

Substituting the values.

5 = 3.80(t/2) + 8.90(t/2)

5 = 12.70(t/2)

t = 10/12.70

t = 0.787 hr × 60 minutes/hr

t = 47.22 minutes

d) average speed = 5miles/0.787hr

v = 6.35 mph

5 0
3 years ago
Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe
Elenna [48]

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2=  0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

3 0
3 years ago
Read 2 more answers
If a trapeze artist rotates once each second while sailing through the air, and contracts to reduce her rotational inertia to on
finlep [7]

Answer:

There are finally 4 rotations per second.

Explanation:

If a trapeze artist rotates once each second while sailing through the air, and contracts to reduce her rotational inertia to one fourth of what it was. We need to find the final angular velocity. It is a case of conservation of angular momentum such that :

I_1\omega_1=I_2\omega_2

Let I_1=I , I_2=\dfrac{I}{4} and \omega_1=1

So,

\omega_2=\dfrac{I_1\omega_1}{I_2}

\omega_2=\dfrac{I\times 1}{(I/4)}

\omega_2=4\ rev/sec

So, there are finally 4 rotations per second. Hence, this is the required solution.

4 0
3 years ago
Pls help
Arte-miy333 [17]

Answer:

sorry I dont now the answer bro i am so sorry xd ;'(

4 0
3 years ago
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