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tatiyna
3 years ago
10

1.) If you make a false statement or commit a forgery about your motor vehicle insurance you can be guilty of a _____ degree mis

demeanor.
a.) Fourth
b.) Second
c.) First
d.) Third

2.) In Florida, when would you be required to have bodily injury liability insurance?
a.) A crash where you collide with a wild animal

b.) A crash where you collide light post

c.) A crash where your vehicle receives more than $200 in damages

d.) A crash where your vehicle has caused damage to the property of others
Physics
2 answers:
krok68 [10]3 years ago
6 0

A person is guilty of second degree misdemeanor if he or she makes a false statement or commits forgery about their motor vehicle’s insurance.

 

You would be required to have bodily injury liability insurance in Florida if you are involved in a crash where your vehicle has caused damage to the property of others.

 

Though, a person is not required to have a Bodily Injury Liability<span> (BI) to legally drive an automobile in the state of Florida. Nevertheless, it would be possible if you are driving under the influence since you are driving while impaired, driving while intoxicated or drunk driving.</span>

Nutka1998 [239]3 years ago
5 0

Answer:

1.) If you make a false statement or commit a forgery about your motor vehicle insurance you can be guilty of a <u>second</u> degree misdemeanor.

2.) You would be required to have bodily injury liability insurance in Florida if you are involved in a crash where your vehicle has caused damage to the property of others.

Explanation:

BRAINLIEST ANSWER PLEASE!

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3N<br> 3 N<br> What is the net force of the box?
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3 years ago
How are the energy conversions of machines similar to the energy conversions in your body
sleet_krkn [62]

Answer:

Explained below

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- chemical to thermal energy to aid in regulating the body temperature.

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6 0
3 years ago
The electronics supply company where you work has two different resistors, R1 and R2, in its inventory, and you must measure the
elixir [45]

Answer:

R₁ = 23.77 ohms and R₂ = 7.92 ohms

Explanation:

When connected in series, the equivalence resistance, R(eq) is given as

R(eq) = (R₁ + R₂)

When connected in parallel, the equivalence resistance, R(eq) is given as

[1/R(eq)] = [(1/R₁) + (1/R₂)]

R(eq) = (R₁R₂)/(R₁ + R₂)

The parallel and series combination are connected to a battery of emf 39.0 V with negligible internal resistance. And the power supplied is measured.

But power supplied is given as

P = IV = (V/R) V = (V²/R)

When connected in series, the power supplied is given as

P = 48.0 W,

V = 39.0 V,

R = R(eq) = (R₁ + R₂)

48 = (39²/R)

R = (39²/48)

R = 31.6875 ohms

R = (R₁ + R₂) = 31.6875

(R₁ + R₂) = 31.6875 (eqn 1)

When connected in series, the power supplied is given as

P = 256.0 W,

V = 39.0 V,

R = R(eq) = (R₁R₂)/(R₁ + R₂)

256 = (39²/R)

R = (39²/256)

R = 5.9414 ohms

R = R(eq) = (R₁R₂)/(R₁ + R₂) = 5.9414

(R₁R₂)/(R₁ + R₂) = 5.9414

But, recall eqn 1

(R₁ + R₂) = 31.6875

(R₁R₂)/(R₁ + R₂) = 5.9414

Substituting for (R₁ + R₂)

(R₁R₂)/(R₁ + R₂) = (R₁R₂)/31.6875 = 5.9414

(R₁R₂) = 31.6875 × 5.9414 = 188.2683

R₁ = (188.2683/R₂)

(R₁ + R₂) = 31.6875

Substituting for R₁

(188.2683/R₂) + R₂ = 31.6875

multiply through by R₂

188.2683 + R₂² = 31.6875R₂

R₂² - 31.6875R₂ + 188.2683 = 0

Solving the quadratic equation

R₂ = 23.77 ohms or 7.92 ohms

If R₂ = 23.77 ohms, R₁ = 7.92 ohms

If R₂ = 7.92 ohms, R₁ = 23.77 ohms

Since the question explains that R₁ > R₂

R₁ = 23.77 ohms and R₂ = 7.92 ohms

Hope this Helps!!!

3 0
3 years ago
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