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Dafna1 [17]
3 years ago
6

Write the overall molecular equation for the reaction of hydroiodic acid ( HI ) and potassium hydroxide. Include physical states

. Enter the formula for water as H 2 O .
Chemistry
1 answer:
Setler [38]3 years ago
3 0

Answer:

HI(aq) + NaOH(aq)-------------> NaI(aq) + H2O(l)

Explanation:

The molecular reaction between hydroiodic acid and aqueous sodium hydroxide is shown above. It is a reaction of one mole of hydroiodic acid with one mole of sodium hydroxide to yield salt and water only. It is a neutralization reaction. Hydrogen iodide dissolves in water to produce hydronium ions which agrees with Arrhenius description of acids. Hydroiodic acid is a strong acid with PKa of -9.3

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For each of the following unbalanced equations, calculate how many grams of each product would be produced by complete reaction
LUCKY_DIMON [66]

Answer:

The answer to your question is

Explanation:

Data

12.5 g of reactant

Balanced Reaction 1

                 TiBr₄ + 2H₂  ⇒  Ti  +  4HBr

Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g

Atomic mass of Ti = 48 g

Molar mass of HBr = 1 + 80 = 81

                 368 g of TiBr₄ ---------------- 48 g of Ti

                    12.5 g of TiBr₄ -------------- x

                    x = (12.5 x 48) / 368

                   x = 1.63 g of Ti

                  368 g of TiBr₄ ----------------4(81) g of HBr

                    12.5 g of TiBr₄ -------------  x

                    x = (12.5 x 324) / 368

                    x = 11 g of HBr

Balanced reaction 2

                  3SiH₄  +  4NH₃  ⇒   Si₃N₄  +  12H₂

Molar mass of SiH₄ = 28 + 4 = 32

Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g

Atomic mass of H₂ = 2 g

                  3(32) g of SiH₄ --------------- 140 g of Si₃N₄

                    12.5 g of SiH₄ --------------  x

                    x = 18.2 g of Si₃N₄

                  3(32) g of SiH₄ --------------- 24 g of H₂

                  12.5 g of SiH₄   --------------  x

                   x = 3.125 g of H₂

5 0
4 years ago
What information is important to include when you are describing the weather?
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5 0
3 years ago
Draw the structure of the major nitration product from the reaction of nitric acid with 1,3‑dimethylbenzene. Show all formal cha
solong [7]

The 2,4 and 5 positions are accessible for nitration of 1,3‑dimethylbenzene. The final product is shown in the image attached.

<h3>What is nitration?</h3>

Nitration is a type of reaction in which the nitro group (-NO2) is introduced to an aromatic ring. We have to note that in the compound 1,3‑dimethylbenzene, the 2,4 and 5 positions are accessible for nitration as shown.

Hence, the nitration of 1,3‑dimethylbenzene occurs  as shown in the image attached with the compound shown being the major product.

Learn more about nitration: brainly.com/question/5346392

7 0
2 years ago
Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and
Assoli18 [71]

Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.

Number of Sigma Bonds:

                                         There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.

Number of Pi-Bonds:

                                  There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.

Number of Electrons in Sigma Bonds:

                                                             As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.

Number of Electrons in Pi Bonds:

                                                       As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.

7 0
3 years ago
Read 2 more answers
Consider the group 1A element sodium (atomic number 11), the group 3A element aluminum (atomic number 13), and the group 7A elem
hoa [83]
Ionization energy is the energy needed to remove a valence electrón from a gaseous atom.

The energy needed to remove the first electron is the first ionization energy.

The stronger the atom atracts its electrons the higher the ionization energy.

A low ionization energy means that the atom may loose one electron easily to form a positive ion (cation)

In the period 3, sodium has the lowest ionization energy (it forms sodium ion easily), aluminium has a higher ionization energy (meaning that it is more difficult to form a positive ion) and Chlorine will never lose an electron to form a positive ion (on the contrary Chlorine is willing to accept one electron from other atom to form a negative ion, i.e. an anion).

The growing of the ionization energy inside a period is due to the size of the growing positive charge (number of protons) in the nucleous, which implies a stronger atraction to the electrons of valence.
3 0
3 years ago
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