1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna1 [17]
3 years ago
6

Write the overall molecular equation for the reaction of hydroiodic acid ( HI ) and potassium hydroxide. Include physical states

. Enter the formula for water as H 2 O .
Chemistry
1 answer:
Setler [38]3 years ago
3 0

Answer:

HI(aq) + NaOH(aq)-------------> NaI(aq) + H2O(l)

Explanation:

The molecular reaction between hydroiodic acid and aqueous sodium hydroxide is shown above. It is a reaction of one mole of hydroiodic acid with one mole of sodium hydroxide to yield salt and water only. It is a neutralization reaction. Hydrogen iodide dissolves in water to produce hydronium ions which agrees with Arrhenius description of acids. Hydroiodic acid is a strong acid with PKa of -9.3

You might be interested in
Specific amino acids that line the selectivity filter of the K channel can dehydrate K and allow passage of that ion but cannot
Bogdan [553]

Answer:

Hi

True

Explanation:

Since on the inner and outer surfaces of the membrane, a series of negatively charged amino acids are found, which increase the local concentration of cations. The path of the ions begins on the inner surface filled with water molecules where the ion can retain its hydration sphere. Two thirds of its interior in the membrane the inside of the channel narrows in the region of the selectivity filter, forcing the ion to separate from the water molecules. Oxygen atoms in the selectivity filter replace the water molecules in the K+ hydration sphere, forming a series of coordination spheres through which the ion moves. The preferential stabilization of K+ against Na+ is the basis of the ion selectivity of this filter.

5 0
3 years ago
In order for a gas to condense to a liquid, the attraction between its molecules _____.
yaroslaw [1]

Answer:

._______.

Explanation:

8 0
3 years ago
Read 2 more answers
How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

8 0
3 years ago
Which material property is most directly related to the x-axis value at the x-intercept of the interatomic force versus distance
Brrunno [24]

Answer:

Explanation:

The mechanical properties of a material affect how it behaves as it is loaded. The elastic modulus of the material affects how much it deflects under a load, and the strength of the material determines the stresses that it can withstand before it fails

3 0
2 years ago
Anyone can help me in science assignment
olya-2409 [2.1K]

Answer:

okay I will help you

Explanation:

okay

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is the mass of 7.91 cm to the power of three piece of lead having a density of 11.34 g/cm to the power of three?
    10·1 answer
  • The heat capacity of chloroform (trichloromethane,CHCl3)
    14·1 answer
  • Describe what the greenhouse effect is and how it is caused on a molecular level.
    14·1 answer
  • 1. Corrosion in metals is an example of what?​
    6·2 answers
  • Which of the following does NOT show the law of conservation of mass?
    5·2 answers
  • PLS HELPPP ASAP
    11·1 answer
  • Which substance has a giant covalent structure and contains atoms of more than one element?A diamondB graphiteC methaneD sand
    11·1 answer
  • Describe the properties of oobleck when it behaves like a solid and a liquid.
    14·1 answer
  • How do we think that Mars lost atmospheric gas?
    14·1 answer
  • Please help with this question!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!