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joja [24]
3 years ago
10

In some regions of the world, forests are cut down and then burned to create room for farmland. How might this local environment

al change affect people living on the East Coast of the United States?
A.
It could help farms to produce more crops by enriching their soil.
B.
It could contribute to rising temperatures and rising sea levels.
C.
It could raise oxygen levels in the ocean, allowing for larger populations of fish.
D.
It could reduce the amount of carbon dioxide that is released into the air.
Chemistry
2 answers:
Firdavs [7]3 years ago
8 0

Answer:It could contribute to rising temperatures and rising sea levels.

Explanation:

The forests are natural sinks for CO2. Forest trees absorb CO2 and release oxygen thereby making the air fresher. CO2 is a greenhouse gas. It is know to adversely contribute to the rising temperature of the earth. This rising temperature of the earth lead to the melting of polar ice caps and consequent rise in sea levels. For this cause, deforestation must be greatly discouraged and afforestation strongly encouraged.

UkoKoshka [18]3 years ago
6 0

The answer is D.

<u>Explanation</u>

Without trees, no carbon dioxide will be released into the air. It would not raise oxygen levels, and it wouldn’t effect rising sea levels.

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I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
Which has a greater volume, 10 grams of water or 10 grams of acetone?
WINSTONCH [101]

Density is defined as the ratio of mass to the volume.

Density = \frac{Mass}{Volume}          (1)

Mass of water = 10 grams

Mass of acetone  = 10 grams

Density of water  = 1 \frac{g}{cm^{3}}

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Put the value of density of water and its mass in equation (1)

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Volume of water =  10 cm^{3}

Put the value of density of acetone and its mass in equation (1)

0.7857 \frac{g}{cm^{3}} =  \frac{10 g}{volume}

Volume of acetone = 12.72 cm^{3}

Thus, volume of acetone is more than volume of water because the density of acetone is lower.

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