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bearhunter [10]
3 years ago
5

Use the periodic table to determine the electron configuration for iodine (i). express your answer in condensed form.

Chemistry
2 answers:
Dovator [93]3 years ago
8 0
Iodine electron configuration is:

1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10  5P^5
when Krypton is the noble gas in the row above iodine in the periodic table,
we can change 1S^2  2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol
[Kr] of Krypton.

So we can write the electron configuration of Iodine:
[Kr] 5S^2 4d^10 5P^5

irga5000 [103]3 years ago
4 0
[Kr]4d^10 5s^2 5p^<span>5. This allows us to determine the shape and energy of the electrons of iodine. There are 3 rules in determining electronic configuration such as AUFBAU's principle,HUND's rule and PAULI EXCLUSION principle.</span>
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A compound has a percent composition of 54.5% carbon, 9.3% hydrogen and 36.2 % oxygen.If its molar mass is 88 g/mol, what is its
drek231 [11]

Answer:

C₄H₈O₂.

Explanation:

  • Firstly, we can calculate the no. of moles (n) of each component using the relation:

<em>n = mass/atomic mass,</em>

mol C = mass/(atomic mass) = (54.5 g)/(12.0 g/mol) = 4.54 mol.

mol H = mass/(atomic mass) = (9.3 g)/(1.0 g/mol) = 9.3 mol.

mol O = mass/(atomic mass) = (36.2 g)/(16.0 g/mol) = 2.26 mol.

  • To get the empirical formula, we divide by the lowest no. of moles (2.26 mol) of O:

∴ C: H: O = (4.54 mol/2.26 mol) : (9.3 mol/2.26 mol) : (2.26 mol/2.26 mol) = 2: 4: 1.

<em>∴ Empirical formula mass of (C₂H₄O) = 2(atomic mass of C) + 4(atomic mass of H) + 1(atomic mass of O) =</em> 2(12.0 g/mol) + 4(1.0 g/mol) + (16.0 g/mol)<em> = 44.0 g/mol.</em>

∴ Number of times empirical mass goes into molecular mass = (88.0 g/mol)/(44.0 g/mol) = 2.0 times.

∴ The molecular formula is, 2(C₂H₄O), that is; <em>(C₄H₈O₂)</em>

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4 years ago
If the answer is correct you will be gifted the Brainliest Answer!
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Answer is C...... .....
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