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bearhunter [10]
3 years ago
5

Use the periodic table to determine the electron configuration for iodine (i). express your answer in condensed form.

Chemistry
2 answers:
Dovator [93]3 years ago
8 0
Iodine electron configuration is:

1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10  5P^5
when Krypton is the noble gas in the row above iodine in the periodic table,
we can change 1S^2  2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol
[Kr] of Krypton.

So we can write the electron configuration of Iodine:
[Kr] 5S^2 4d^10 5P^5

irga5000 [103]3 years ago
4 0
[Kr]4d^10 5s^2 5p^<span>5. This allows us to determine the shape and energy of the electrons of iodine. There are 3 rules in determining electronic configuration such as AUFBAU's principle,HUND's rule and PAULI EXCLUSION principle.</span>
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What experimental method has allowed scientists to estimate atomic and ionic radii?
KIM [24]
The meaning of the atomic radius is a large portion of the normal internuclear separation of an atom. It isn't conceivable to deal with one atom. In any case, here internuclear remove does not mean measurement of a solitary particle but rather it implies the separation between the core of two atoms of a similar component.
8 0
3 years ago
Element: calcium symbol: Ca Atomic weight: g Mass of one mole: g/mol
Elena-2011 [213]

153g/mols I think this is the answer but not 100% sure.


6 0
3 years ago
The next 11 questions are related to the titration of 40.00 mL of a 0.0900 M acetic acid solution with 0.0700 M KOH. Assume that
liberstina [14]

Answer:

2.9 is the initial pH of the analyte solution.

Explanation:

The dissociation constant of acetic acid as per theoretical value =  K_a

K_a=10^{-4.756}=1.8\times 10^{-5}

The initial concentration of acetic acid = c = 0.0900 M

HAc\rightleftharpoons Ac^-+H^+

initially

c       0    0

At equilibrium

(c-x)      x  x

The expression of dissociation constant :

K_a=\frac{[Ac^-][H^+]}{[HAc]}

1.8\times 10^{-5}=\frac{x\times x}{(c-x)}

1.8\times 10^{-5}=\frac{x\times x}{(0.0900-x)}

Solving for x:

x = 0.001264 M

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2.9 is the initial pH of the analyte solution.

4 0
3 years ago
In order to make 0.500 L of a 0.475 M solution, you will need to weigh out how many grams of sucrose (MM = 342 g/mol)?
elixir [45]

The first step to solve this problem is to multiply the volume of solution times its concentration to find the number of moles needed, remember that M=mol/L:

0.500L\cdot\frac{0.475mol}{L}=0.2375mol

Now, use the molar mass of sucrose to find the number of grams needed to make the solution. This is, multiply the number of moles needed times the molar mass:

0.2375mol\cdot\frac{342g}{mol}=81.225g

It means that to make 0.500L of a 0.475M you will have to weigh 81.225g of sucrose.

4 0
1 year ago
I need help pls I will give you brainlist
White raven [17]

Answer:

I think it is the second one

Explanation:

Because what the cold water did to the table salt, is that it separated its molecules dissolving the salt.

even though the rock salt was in hot water it was a bigger particle. But the big difference was only because the water temperature ️.

5 0
2 years ago
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