i love math but sadly i am dumb
<span><span>Iron, Wrought 1482 - 1593- 2900</span><span>Iron, Gray Cast1127 - 1204 - 2200</span><span>Iron, Ductile1149</span></span>
The mass percent of each compound is
- (NaBr*2H2O)=85.71 percent
- (MgBr2*6H2O)=14.29 percent
<h3>The mass percent equation is as follows.</h3>
The formula mass percent is the most effective way to express mass percent: mass percent = (mass of chemical x total mass of compound) times 100. Add 100 to the top value to get the value expressed as a percentage.
<h3>What percentage by mass does a solution have?</h3>
By multiply the grams of solute per gram of solution by 100, it is possible to get the mass percent of a solution.
The molar mass of each element and the mass of each element contained in a mole of the compound are both solved for in the Mass Percent formula.
Learn more about Mass Percent here
brainly.com/question/26150306
#SPJ4
Answer:
Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.
Explanation:
Peptide bond is a form of covalent bond and it is Amide type that is formed between two molecules when carboxyl group react with one molecule of amino group to release molecule of water.The peptide bond are in form pseudo-double bond characteristic; rigid, planar, and stronger than a typical Carboxyl nitrogen single bond.
Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.
Answer:
CaSO₄ (calcium suflate) is the precipitate formed
Explanation:
We can think the reactants:
BeSO₄ → Beryllium sulfate
Ca(OH)₂ → Calcium hydroxide
The reaction is:
Be₂SO₄ + Ca(OH)₂ → CaSO₄ ↓ + Be(OH)₂
We call it as a double-replacement reaction because two ions exchange places from 2 compounds to form two new compounds.
Sulfates can always make precipitate with the elements from group 2, Ca, Ba and Mg.
Hydroxides from group 2 are solubles, so we complete states:
BeSO₄ (aq) + Ca(OH)₂ (aq) → CaSO₄ ↓ (s) + Be(OH)₂ (aq)