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Stella [2.4K]
4 years ago
8

D+g/h for d =29, for g=16,h=9

Mathematics
2 answers:
dsp734 years ago
8 0

Answer: 31  and 1/9

Step-by-step explanation:

d =29, for g=16,h=9

replace values of each number in equati/on:

d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9

dangina [55]4 years ago
3 0

\text{Plug in the values to their correct variables and solve:}\\\\\frac{d+g}{h}\\\\\frac{29+16}{9}\\\\\text{Solve:}\\\\\frac{29+16}{9}\\\\\frac{45}{9}\\\\\text{Divide 45 by 9}\\\\\boxed{5}

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The given addition exercise is:

\frac{2}{5}+\frac{1}{3}

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}

Multiply 1/3 by 5/5

\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}

The addition becomes

\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

Therefore, we can fill in the vacant boxes as shown below:

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1 year ago
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