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Stella [2.4K]
3 years ago
8

D+g/h for d =29, for g=16,h=9

Mathematics
2 answers:
dsp733 years ago
8 0

Answer: 31  and 1/9

Step-by-step explanation:

d =29, for g=16,h=9

replace values of each number in equati/on:

d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9

dangina [55]3 years ago
3 0

\text{Plug in the values to their correct variables and solve:}\\\\\frac{d+g}{h}\\\\\frac{29+16}{9}\\\\\text{Solve:}\\\\\frac{29+16}{9}\\\\\frac{45}{9}\\\\\text{Divide 45 by 9}\\\\\boxed{5}

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Answer:

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3 years ago
Solve the equation using the quadratic formula : x^2-10x+25=18
Sever21 [200]
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x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


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3 years ago
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Step-by-step explanation:

6 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

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\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

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\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

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\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

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\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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