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Stella [2.4K]
3 years ago
8

D+g/h for d =29, for g=16,h=9

Mathematics
2 answers:
dsp733 years ago
8 0

Answer: 31  and 1/9

Step-by-step explanation:

d =29, for g=16,h=9

replace values of each number in equati/on:

d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9

dangina [55]3 years ago
3 0

\text{Plug in the values to their correct variables and solve:}\\\\\frac{d+g}{h}\\\\\frac{29+16}{9}\\\\\text{Solve:}\\\\\frac{29+16}{9}\\\\\frac{45}{9}\\\\\text{Divide 45 by 9}\\\\\boxed{5}

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The answer is the last one D that is the correct answer 
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7 0
3 years ago
Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0
2 years ago
Ariana bought 5 dozen pears at $36 per dozen . She discovered that 7 were rotten and she sold the rest at $4.50 each . Calculate
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Step-by-step explanation:

1 dozen = 12 pears

12 pears = $36

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= 60 x 3

= $180

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= $4.50 x (5x12-7)

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= $238.50

Profit/Loss = Sale of Pears - Total Cost of Pears

= $238.50 - $180

= $58.50

Ariana made a profit of $58.50.

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