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Ahat [919]
3 years ago
9

Please help ill mark brilliant​

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

i think its 12

Step-by-step explanation:

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Simplify the expression 6(6-2x)- 10( + 1)​
dexar [7]

Answer:

−12x+26

Step-by-step explanation:

i said so kid

Use https://www.mathpapa.com/algebra-calculator.html

3 0
3 years ago
Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
chubhunter [2.5K]

Answer:

±2

Step-by-step explanation:

For simplicity let's take a look at a general third order polynomial:

ax^3 + bx^2 + cx + d.  In this particular case,

rational roots have the form ±d/±a.  Note that these are fractions/ratios.  Beyond that, we factor d and choose numerators ±(all possible whole number factors of d, dividing these results by all possible factors of a.

Looking at 4x^3 + 9x^2 - x + 10 = 0, we see that d = 10 and that factors of d include ±1, ±2, ±5 and ±10.  a = 4 and factors of a include ±1, ±2, ±4.

So, any rational roots of the given polynomial will stem from the possible rational roots

±1    ±2    ±5    ±10    ±1    ±2    ±5    ±10

--- , ----- , -----, ------- , ---- , ----- , --- , ------ , and so on,

±1    ±1     ±1      ±1      ±2    ±2   ±2     ±2

until you have used up all of the possible factors of 10 and all of the possible factors of 4.  

Of the four possible rational roots you have shared, only ±2 (which would actually be ±2 / ±1) is acceptable.

4 0
3 years ago
Read 2 more answers
Sweet T has 2 orange picks of every green pick. If 6 of the picks are green, how many picks are orange?
Lesechka [4]
12 picks are orange.
4 0
3 years ago
Read 2 more answers
Find the area of this circle
IRISSAK [1]

Answer:

78.5398 cm^2

Step-by-step explanation:

r = 1/2*d => d = 10 cm

r = 5

A = pi*r^2

= pi*5^2 => 3.1415*5^2

=> 78.5398

3 0
2 years ago
Given that cosec A= -2, sec B= -2, A and B lie in the same quadrant. Find sin (2A+2B)
sergij07 [2.7K]

Answer:

sin (2A+2B) = 0

Step-by-step explanation:

Given that,

cosec A= -2 and sec B= -2, A and B lie in the same quadrant.

We need to find the value of sin (2A+2B).

A=cosec^{-1}(-2)\\\\=-30

And

B=\sec^{-1}(-2)\\\\=120^{\circ}

To find the value of sin (2A+2B) as follows :

sin [2(-30)+2(120)] = sin (-60+240)

=sin (180)

= 0

So, the value of sin (2A+2B) is qual to 0.

7 0
2 years ago
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