Answer:
(d) 
General Formulas and Concepts:
<u>Algebra I</u>
- Functions
- Function Notation
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Property [Addition/Subtraction]: ![\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%20%2B%20g%28x%29%5D%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5D%20%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bg%28x%29%5D)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<u>Step 2: Differentiate</u>
- Basic Power Rule:
- Simplify:
- Multiply:
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
Answer:
i ) $96120
ii ) Singular adult fee in 2012: $186.91
Step-by-step explanation:
( i )
To find the costs of all 560 peoples you:
Multiply the amount of people by the fee,
440 × 198 = $87120
120 × 120 = $9000
Add these go get the sum of member fees: $96120
( ii )
First calculate what 1% of the adult fee would be:
198 ÷ 100 = 1.98 = 1%
Then calculate what 0.1% of the fee:
1.98 ÷ 10 = 0.198 = 0.1%
Now multiply 5 by the value of 1% to get 5% :
5 × 1.98 = 9.9
Then multiply 6 by the 0.1% to get 0.6% :
0.198 × 6 = 1.188
Add these numbers together to get:
1.188 + 9.9 = $11.088 = 5.6%
Due to the fact this question is referring to money we will round this number 2 decimal places (as money does not exceed 2dp)
$11.09
We now subtract this from the 2013 fee to find out the 2012 fee
$198 - $11.09 = $186.91
$186.91 was the cost of a singular adult fee in 2012
The problem with this conclusion is that there is missing data.
In order for there to be a conclusion you must test it multiple times in order to see how certain the conclusion is.
Good Luck! :)
❤️ ❤️ ❤️
Answer:
3×10^4
Step-by-step explanation:
The desired factor is found by calculating the ratio of the two numbers:
k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4
The first number is 3×10^4 = 30,000 times as much as the second number.
Answer:
is it radius or diameter?
