0A: accelerating
AB: constant
BC: decelerating
CD:at rest
DE:accelerating
EF: constant
hope this helps
Answer: 30 metres
Explanation:
Initial velocity of object = 120m/s
Time taken = 4.0s
Distance covered by object = ?
Recall that distance = (Change in velocity / Time taken)
Distance = (120m/s)/4.0s
= (120m/s) / 4.0s
= 30m
Thus, the object will be 30 metres high
The impulse J is equal to the magnitude of the force applied to the cannonball times the time it is applied:
But the impulse is also equal to the change in momentum of the cannonball:
If we put the two equations together, we find
And since we know the magnitude of the average force and the time, we can calculate the change in momentum: