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Rina8888 [55]
3 years ago
5

Which orbitals can overlap to form a pi bond?

Chemistry
2 answers:
Yanka [14]3 years ago
5 0

The correct option is A)

They overlap to form a pi bond


And yes, if a question of yours gets deleted, the amount of points you used are automatically transferred back to your account

Hope this helps

-AaronWiseIsBae

lions [1.4K]3 years ago
5 0

<u>Ans: A) two p-orbitals</u>

The connectivity between two atoms in a given molecule can be via single bonds or multiple bonds.

-Single bonds are categorised as sigma bonds

-Multiple bonds can be:

1) Double bond = 1 sigma + 1 pi bonds

2) Triple bonds = 1 sigma + 2 pi bonds

Sigma bonds are usually formed by the overlap of 2 s-orbitals or some hybrid orbitals that is a combination s,p (or even d-) orbitals

Pi orbitals however are formed by the sideways of overlap of unhybridized p-orbitals.

For example:

Ethylene : H2C=CH2 has a double bond which is a combination of a sigma bond and a pi bond

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3 years ago
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What is the wavelength (in nm) of
LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

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6 0
3 years ago
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory, what hybrid orbitals are used by
Vlad1618 [11]

Answer:

sp³

Explanation:

Number of hybrid orbitals = ( V + S - C + A ) / 2

Where

H is the number of hybrid orbitals

V is the valence electrons of the central atom = 5

S is the number of single valency atoms = 4

C is the number of cations = 1

A is the number of anions = 0

For PCl₄⁺

Applying the values, we get:

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5 0
3 years ago
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if 15 mol C is mixed with 10 mol O2 which reactant is the limiting reactant? Which reactant would be the excess reactant?
ioda

Answer:

C is the excess reactant.

Explanation:

Reaction is C + O2 --> CO2

1mol of C required to react with 1mol O2

Therefore 15 - 10 = 5moles of C will be in excess

6 0
3 years ago
If 5 moles of P4 reacted with 22 moles Cl2 according to the above reaction, determine:
GaryK [48]

Solution:

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a) By stoichoimetry If 6 moles of Cl_2 gives 4 mole of PCl_3 , then 22 moles of Cl_2 will give: \frac{4}{6}\times 22=\frac{44}{3}=14.66 moles of PCl_3

b) If 6 moles of Cl_2 reacts with one mole of P_4 , then 22 moles of Cl_2 will react : \frac{1}{6}\times 22=\frac{11}{3}=3.66 moles of P_4

Moles of P_4  left after the reaction = 5-3.66=\frac{4}{3}=1.34 moles.

c) 0 Moles of Cl_2 , since it is present in less amount it will get completely consumed in the reaction. Hence, it is limiting reagent.



7 0
3 years ago
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