All categories

3 years ago

Help please! I don’t know what subject to pick this is science tho!!!!!!!!!!!!!!!

Chemistry

1 answer:

miss Akunina [59]3 years ago

5 0

Answer:

Explanation:

Because it decreases from October trough december

You might be interested in

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$

$2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})$

$\mathbf{C_v = 9.1 \ wt\%}$

4 0

3 years ago

Find the mass of carbon in a sample of hcn with a mass of 3.37 g

dsp73

Answer:

我實際

Explanation:

我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈

7 0

3 years ago

What is called the powerhouse of a cell because it breaks down nutrients to help make the major energy source of the cell?.

Lisa [10]

MITOCHONDRIA.
The powerhouse of a cell is Mitochondria, don’t you even forget this.

6 0

3 years ago

Every organism has a unique common name.

prohojiy [21]

Answer true

Explanation:

Every recognized species on earth (at least in theory) is given a two-part scientific name. ... These naming rules mean that every scientific name is unique. For example, if bluegill sunfish are given the scientific name Lepomis macrochirus, no other animal species can be given the same name

3 0

3 years ago

Read 2 more answers

A rock displaces 475ml of water what’s its volume

grin007 [14]

Answer:

The rock displaces 475 mL of water.

475 mL is the volume of the rock.

1 mL = 1 cm^3

The mass is just density times volume.

m = 475 * 2.5 = 125 g

Explanation:

5 0

3 years ago