All of them are correct! good!!
These are terms that we use in physics
V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M
Number of moles HNO₃ :
n = M x V
n = 1.50 x 0.05
n = 0.075 moles of HNO₃
HNO₃ + NaOH = H₂O + NaNO₃
1 mole HNO₃ -------- ---1 mole NaOH
0.075 moles HNO₃ ---- ?
moles NaOH = 0.075 * 1 / 1
= 0.075 moles of NaOH
V ( NaOH ) :
M = n / V
0.81 = 0.075 / V
V = 0.075 / 0.81
V =<span> 0.0925 L or 92.5 mL </span>
<span>hope this helps!</span>
12 moles H2O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
