Answer:
A sonar device sends pulses of sound waves down through the water. When these pulses hit objects like fish, vegetation or the bottom, they are reflected back to the surface. The sonar device measures how long it takes for the sound wave to travel down, hit an object and then bounce back up.
Answer:
Work done, W = 255.21 J
Explanation:
It is given that,
Rotational inertia of the wheel, ![I=16\ kg-m^2](https://tex.z-dn.net/?f=I%3D16%5C%20kg-m%5E2)
Angular displacement, ![\theta=2\ rev=12.56\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D2%5C%20rev%3D12.56%5C%20rad)
Initial angular velocity, ![\omega_i=7\ rad/s](https://tex.z-dn.net/?f=%5Comega_i%3D7%5C%20rad%2Fs)
Final angular velocity, ![\omega_f=9\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%3D9%5C%20rad%2Fs)
Firstly finding the angular acceleration of the wheel using the equation of rotational kinematics as :
![\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cdfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Ctheta%7D)
![\alpha =\dfrac{9^2-7^2}{2\times 12.56}](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cdfrac%7B9%5E2-7%5E2%7D%7B2%5Ctimes%2012.56%7D)
![\alpha =1.27\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D1.27%5C%20rad%2Fs%5E2)
Work done by the torque is given by :
![W=\tau\times \theta](https://tex.z-dn.net/?f=W%3D%5Ctau%5Ctimes%20%5Ctheta)
![W=I\times \alpha \times \theta](https://tex.z-dn.net/?f=W%3DI%5Ctimes%20%5Calpha%20%5Ctimes%20%5Ctheta)
![W=16\times 1.27 \times 12.56](https://tex.z-dn.net/?f=W%3D16%5Ctimes%201.27%20%5Ctimes%2012.56)
W = 255.21 J
Out of given options, the correct option for the work done by the torque is 255.21 J. Hence, this is the required solution.
Answer:
In the parallel plate capacitor
The capacitance will decrease between the plates.
The voltage will increase between the plates.
Explanation:
When the distance between the plates increase, then the voltage also increases as it varies with the separation of plates. However the capacitance will decrease upon increasing the distance. As the capacitance depends upon the electric field between the plates. Field is stronger when the plates are closer so capacitance increase. Field will be weaker upon increasing the distance and hence the capacitance decreases.
Answer:
48.63 mL
Explanation:
Using Charles's law
Given ,
V₁ = 29 mL
V₂ = ?
T₁ = 25 °C
T₂ = 500 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25 + 273.15) K = 298.15 K
Using above equation as:
<u>New volume = 48.63 mL</u>