First you must calculate the speed of Amy and speed of Bill.
![d=14.4km=14400m \\t_a=40min=2400sec \\t_b=20min=1200sec \\s_a=\frac{d}{t_a}=\frac{14400m}{2400sec}=\boxed{6\frac{m}{sec}} \\s_b=\frac{d}{t_b}=\frac{14400m}{1200sec}=\boxed{12\frac{m}{sec}} \\](https://tex.z-dn.net/?f=%3C%2Fp%3E%3Cp%3Ed%3D14.4km%3D14400m%20%5C%5C%3C%2Fp%3E%3Cp%3Et_a%3D40min%3D2400sec%20%5C%5C%3C%2Fp%3E%3Cp%3Et_b%3D20min%3D1200sec%20%5C%5C%3C%2Fp%3E%3Cp%3Es_a%3D%5Cfrac%7Bd%7D%7Bt_a%7D%3D%5Cfrac%7B14400m%7D%7B2400sec%7D%3D%5Cboxed%7B6%5Cfrac%7Bm%7D%7Bsec%7D%7D%20%5C%5C%3C%2Fp%3E%3Cp%3Es_b%3D%5Cfrac%7Bd%7D%7Bt_b%7D%3D%5Cfrac%7B14400m%7D%7B1200sec%7D%3D%5Cboxed%7B12%5Cfrac%7Bm%7D%7Bsec%7D%7D%20%5C%5C%3C%2Fp%3E%3Cp%3E)
Now calculate the difference between Bill's speed and Amy's speed.
![\Delta{s}=s_b-s_a=12\frac{m}{sec}-6\frac{m}{sec}=\boxed{6\frac{m}{sec}}](https://tex.z-dn.net/?f=%3C%2Fp%3E%3Cp%3E%5CDelta%7Bs%7D%3Ds_b-s_a%3D12%5Cfrac%7Bm%7D%7Bsec%7D-6%5Cfrac%7Bm%7D%7Bsec%7D%3D%5Cboxed%7B6%5Cfrac%7Bm%7D%7Bsec%7D%7D%3C%2Fp%3E%3Cp%3E)
Amy's average speed is not faster. Bill's average speed is faster than Amy's by 6 m/sec.
Hope this helps.
r3t40
Answer:
fossil fuels are natural and limited, nuclear is man made and more toxic
Explanation:
Answer:
It will take 6.1seconds for the projectile to hit the ground.
Explanation:
In projectile, the time taken by an object to spend in air is its time if flight.
Time of flight = 2Usin(theta)/g
where u is the initial velocity = 75m/s, theta = 24°, g = 10m/s²
Time of flight = 2(75)sin24°/10
Time of flight = 150sin24°/10
Time of fight = 6.1seconds.
This means that it will take 6.1seconds for the projectile to hit the ground.
Answer:
Objects with greater mass have a stronger force of gravity between them. Objects that are closer together have a stronger force of gravity between them.
Explanation:
Newton's law states that the strength of gravity between any two objects depends on two factors: the masses of the objects and the distance between them.
Answer:
Explanation:
Left block is on surface with higher inclination so it will go down . If T be tension
For motion of block A ,
net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .
ma = mgsin60 - T - mg cos 60 x .1
10a = 277.13 - T - 16
= 261.13 - T
T = 261.13 - 10a
For motion of block B
T - mg sin30 - mgcos30 x μ = ma
T- 160 - 27.71 = 10 a
261.13 - 10a - 160 - 27.71 = 10a
73.42 = 20a
a = 3.67 ft / s²
common acceleration = 3.67 ft / s²