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Murrr4er [49]
3 years ago
5

Which of the following groups of moon phases are above the horizon at 8 am?

Physics
1 answer:
Mandarinka [93]3 years ago
4 0

The correct option is:

B. new Moon, third quarter, and waning gibbous

<u>Explanation: </u>

Firstly, for the moon to be visible at all, even during the night, it has to be above the horizon so as to be visible.  

• The new/full moon rises when the sun is about to set, and only fades  when the sun starts to rise in the sky. This is how we see the full moon in the sky, which mostly the sun’s light reflecting on the surface of the moon.

• Third quarter moon rises during midnight and sets during mid day, hence we see the crescent part of the moon.

• Waning gibbous moon rises quite later into the night, hence sets later in the day, therefore we  see it in the morning sky.

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lapo4ka [179]

Answer:A.325J

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8 0
2 years ago
a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will hap
bogdanovich [222]

An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity

What will happen to the spacecraft is given by option C. from among the possible question options.

C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force

Reason:

<em>The possible question options obtained from a similar question includes;</em>

<em>A. The spacecraft will move for some time then stop slowly</em>

<em>B. Air resistance will prevent the spacecraft from moving</em>

<em>C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it</em>

<em>D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only</em>

The state of the space craft = Motionless

Location of the spacecraft = Deep space

Type of force applied = Quick push

The statement that describes what will happen = Required

Solution;

Let <em>F</em>, represent the force applied, and let Δt be the duration of the applied force, we have;

The impulse of the force, F × Δt = m·(v₂ - v₁)

Where;

m = The mass of the spacecraft

v₁ = The initial velocity of the spacecraft = 0

v₂ = Final velocity of the spacecraft

Plugging in v₁ = 0, gives;

F × Δt = m·v₂

The space craft is given a velocity, <em>v₂</em>, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it

Therefore, the correct option is option C. <u>The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force</u>

<u />

Learn more about Newton's First Law of Motion here:

brainly.com/question/20841616

8 0
3 years ago
Calculate the efficiency of a machine if the input work is 200J and the output work is 150J.​
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Answer:

75% is the efficency of this maxhine

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3 years ago
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Answer:

Q1: (a)

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45 \times  {10}^{ - 2} m

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1km = 10 {}^{3} m \\ 6378km \times  {10}^{ 3}

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diameter = 2r

in this i don't know which choice is the right answer

Q3:

1gram = \:  {10}^{ - 3} kg

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250 \times  {10}^{ - 3}  = 2.5 \times  {10}^{ - 1} kg

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A wave is incident on the surface of a mirror at an angle of 41° with the normal. what can you say about its angle of reflection
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It's angle of reflection must be 41 degrees

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