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zhenek [66]
2 years ago
10

Explain why Earth is not a perfect sphere?

Physics
1 answer:
miss Akunina [59]2 years ago
6 0
The answer is C hope it helped
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Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45-m-diamete
Margarita [4]

Explanation:

It is given that,

Diameter of the semicircle, d = 45 m

Radius of the semicircle, r = 22.5 m      

Speed of greyhound, v = 15 m/s

The greyhound is moving under the action of centripetal acceleration. Its formula is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(15)^2}{22.5}

a=10\ m/s^2

We know that, g=9.8\ m/s^2

a=\dfrac{10\times g}{9.8}

a=1.02\ g

Hence, this is the required solution.                                              

5 0
3 years ago
The space velocity of a star is 120 km/s and its radial velocity is 72 km/s. what is its tangential velocity?
Marina CMI [18]
You divide 120 and 72 and get 1.67 repeated i think
3 0
3 years ago
A particle has a de Broglie wavelength of 2.1 × 10-10m. Then its kinetic energy increases by a factor of 3. What is the particle
svlad2 [7]

Answer:

\lambda' =1.21\times 10^{-10}\ m

Explanation:

given,

de broglie wavelength of the particle = 2.1 × 10⁻¹⁰m

Kinetic energy increase factor = 3

de broglie  wavelength of new particle = ?

we know,

P = \dfrac{h}{\lambda}

Kinetic energy

K =\dfrac{p^2}{2m}

K =\dfrac{h^2}{2m\lambda^2}...........(1)

Kinetic energy of other particle

3K =\dfrac{h^2}{2m\lambda'^2}............(2)

dividing equation (1)/(2)

\dfrac{1}{3} =\dfrac{\lambda'^2}{\lambda^2}

\lambda' = \dfrac{\lambda'}{\sqrt{3}}

\lambda' = \dfrac{2.1\times 10^{-10}}{\sqrt{3}}

\lambda' =1.21\times 10^{-10}\ m

6 0
3 years ago
Two parallel plates of area 7.34 x 10^-4 m^2 have 5.83 x 10^-8 C of charge placed on them. A 6.62 x 10^-6 C charge q1 is placed
inn [45]

Answer:

* if the two plates have the same charge sign       F_net = 0

*if one plate is positive and the other is negative   F_net = 59.4 N

Explanation:

The electric field created by a parallel plate is

           E = \frac { \sigma }{2 \epsilon_o  }

where sigma is the charge density

          σ = Q / A

we substitute

           E = \frac{Q}{A \ 2 \epsilon_o }

           E = \frac{ 5.83 \ 10^{-8} }{7.34 \ 10^{-4}\ 2 \ 8.5 \ 10^{-12} }

           E = 4.487 10⁶ N / C

the electric force is

          F = E / q

in this force it is a vector, so if the charges are of the same sign they repel and if they are of the opposite sign they attract. In this case, the test load is between the two plates that have the same load sign, so the forces are in the opposite direction.

* if the two plates have the same charge sign

          F_net = F₁ - F₂

          F_net = q (E₁ -E₂)

since the electric field does not depend on the distance

           E₁ = E₂

in consecuense  

           F_net = 0

In a more interesting case

*if one plate is positive and the other is negative

           F_net = F₁ + F₂

           F_net = q (E₁ + E₂) = 2 q E₁

           F_net = 2 6.62 10⁻⁶  4.487 10⁶

           F_net = 59.4 N

net force goes from positive to negative plate

7 0
3 years ago
How will sunlight most likely affect a black shirt on a hot summer day?
Novosadov [1.4K]
It will make the shirt very hot because the color black absorbs all colors of the color spectrum. So never war a black shirt on a sunny day.<span />
3 0
3 years ago
Read 2 more answers
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