To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be
Here,
m = mass
g = Acceleration due to gravity
h = Height
our values are,
Replacing,
Then the height is 32.83m.
Answer:
2a. 24 m³
2b. 19200 Kg
2c. 192000 N
2d. 16000 N/m²
Explanation:
2a. Determination of the volume of paraffin.
Length (L) = 4 m
Width (W) = 3 m
Height (H) = 2 m
Volume (V) =?
V = L × W × H
V = 4 × 3 × 2
V = 24 m³
Therefore the volume of paraffin is 24 m³
2b. Determination of the mass of paraffin.
Volume (V) = 24 m³
Density (ρ) = 800 Kg/m³
Mass (m) =?
ρ = m / V
800 = m / 24
Cross multiply
m = 800 × 24
m = 19200 Kg
Therefore, the mass of paraffin is 19200 Kg
2c. Determination of the weight of paraffin.
Mass (m) = 19200 Kg
Acceleration due to gravity (g) = 10 N/Kg
Weight (W) =?
W = m × g
W = 19200 × 10
W = 192000 N
Therefore, the weight of paraffin is 192000 N
2d. Determination of the pressure.
Density (ρ) = 800 Kg/m³
Depth (h) = 2 m
Acceleration due to gravity (g) = 10 N/Kg
Pressure (P) =?
P = ρgh
P = 800 × 10 × 2
P = 16000 N/m²
Answer:
22
Explanation:
all the resistance numbers added together 2.0+6.0+10.0+4.0
<em>resistance</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em> </em><em>:</em><em> </em><em>v</em><em> </em><em>be</em><em>t</em><em>t</em><em>a</em><em>r</em><em>y</em><em> </em><em>=</em><em> </em><em>v</em><em>1</em><em> </em>+ <em>v</em><em>2</em><em> </em><em>+</em><em> </em><em>v</em><em>3</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>
Because not all of the universe can be seen with a visible spectrum
