Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con

Question

3 years ago

11

30 min, sabiendo que la velocidad media del avión es de 910 km/hr ¿que espacio recorrió el avión?

1 answer:

Vitek1552 [10] · Answer 1 · 2022-08-28T23:21:26+03:00

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

Stopping time = 11hrs 30min

Speed = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

Speed = $\frac{distance}{time}$

Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

Input the parameters:

Distance = 910km/hr x 4.5hrs = 4095km

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