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mr_godi [17]
3 years ago
11

Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con

30 min, sabiendo que la velocidad media del avión es de 910 km/hr ¿que espacio recorrió el avión?
Physics
1 answer:
Vitek1552 [10]3 years ago
6 0

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

Stopping time = 11hrs 30min

Speed  = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

 Speed = \frac{distance}{time}

 Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

  Input the parameters:

  Distance = 910km/hr x 4.5hrs = 4095km

learn more:

Speed brainly.com/question/10048445

#learnwithBrainly

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