3 years ago

Pls help me

Mathematics

2 answers:

Bingel [31]3 years ago

8 0

1. x+16
2. x-8
3. 12÷x

mylen [45]3 years ago

7 0

1.x+16
2.x-8
3.12/x
these are the algebraic expressions

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I’m so confused help please

lozanna [386]

Answer:

B. 0

Step-by-step explanation:

If you subtract the right side expression and simplify, you get ...

4/5(20x +5) -(16x -2) = 0

16x +4 -16x +2 = 0

6 = 0 . . . . . . . . . . . . false

There is no value of x that will make this true. There are no solutions.

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2 years ago

Please help me with this!<br><br><br> show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}

Llana [10]

The set $\{x\mid x^4-x^3-x^2-6x+6=0\}$ is the set of all values of $x$ that are solutions to the given equation. So all you need to do is check whether $x=1$ and $x=2$ satisfy the equation.

$x=1\implies 1^4-1^3-1^2-5+6=0$

$x=2\implies2^4-2^3-2^2-10+6=0$

The equation holds, so both 1 and 2 are solutions, and hence $\{1,2\}$ is a subset of the solutions.

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3 years ago

What are the solutions of the system? Solve by graphing. y=x^2-2x-1, y = -2

pychu [463]

I used desmos online.

(1,-2)

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3 years ago

X+2y =3 -x+y=6 elimination

Neko [114]

You can try using the formula y=mx+b

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Will mark Brainlest, if you answer fast!!!

noname [10]

Answer:

-2x

Step-by-step explanation:

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