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d1i1m1o1n [39]
4 years ago
5

A ball is thrown from an initial height of

Mathematics
1 answer:
ExtremeBDS [4]4 years ago
6 0
We are using simple gravity as a constant (ignoring air resistance and change in height)

a=-g  integrating with respect to t

v=-gt+C  where C is the initial velocity...

v=-gt+29  integrating again with respect to time...

h=(-gt^2)/2+29t+C  where C is the initial height of the ball...

h(t)=-16t^2+29t+4
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