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Leto [7]
4 years ago
13

What is greater 0.72 l or 572 ml

Mathematics
1 answer:
8090 [49]4 years ago
4 0
.72 L is equal to 720 mL.
So .72 L is the correct answer
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Convert the following to standard form, then write
Ivahew [28]

Answer:

f(x)=x^2+6x+9

Step-by-step explanation:

We are required to represent the expression given in the standard form to the quadratic form

Given

f(x) = (x + 3)^2

let us square the given expression

f(x)=(x+3)(x+3)

open brackets

f(x)=x^2+3x+3x+9

sum the similar terms

f(x)=x^2+6x+9

6 0
3 years ago
Which of the following are possible rational roots of the polynomial function f(x)=5x^2-3x+3
yanalaym [24]

You didn't post any option, but the ration roots theorem states that all possible rational roots of a polynomial come in the form

\pm\dfrac{p}{q}

where p divides the constant term and q divides the leading term of the polynomial. So, in your case, p divides 3 (i.e. it is 1 or 3), and q divides 5 (i.e. it is 1 or 5).

So, the possible roots are

\pm 1,\quad \pm 3,\quad \pm\dfrac{1}{5},\quad \pm\dfrac{3}{5}

For the record, this parabola has no real roots.

7 0
3 years ago
Read 2 more answers
Christina's ice cream parlor sold 60 vanilla cones on the first day of summer. If the goal is to increase the number of vanilla
dimaraw [331]

1280 cones because you would add 60 +4 and multiply by 20, and would get 1280 cones.

7 0
3 years ago
Which of the following ordered pairs represents a solution<br> to the linear equation y = 5 - X?
lina2011 [118]

Answer:

You have to put an attachment file of the options or what x equals.

Step-by-step explanation:

4 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
4 years ago
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