Answer:
B
pls correct me if im wrong
Answer:
Concentration of the reactants decreases;
Rate of a reaction decreases
Explanation:
Since volume is held constant in a solution, the concentration of the reactants will decrease.
Simply speaking, concentration is the ratio between moles and volume. Volume is constant here. Over time, the number of moles of the reactants will decrease, as they react to produce products and they are disappearing. Since moles are directly proportional to concentration, this implies that concentration will also decrease, while the concentration of the products will increase, as they're formed.
The rate of a reaction decreases as the reaction continues, as we have lower and lower amounts of the reactants remaining in the solution as time progresses. Therefore, the probability of a successful collision leading to products decreases.
Answer:
Answer below (in explanation)
Explanation:
First find the average atomic mass of the element in question (on the periodic table)
Set up the relative abundance formula: (M1)(x) + (M2)(1-x) = M(E)
Where M1 = Mass of the first isotope, X = Relative abundance, M2 = mass of the second isotope, M(E) = Atomic mass of the element
Plug in your values (i'll use nitrogen as an example) :
(background info: The mass of one isotope, nitrogen-14, is 14.003 amu and another isotope, nitrogen-15, is 15.000 amu, find the relative abundance of the isotopes.
14.003x + 15.000(1-x) =14.007
Use algebra and solve for X. First use distributive property, combine like terms, and solve for X.
It would equal X = 0.996. Multiply by 100 to get a proper percentage and the percentage abundance of Nitrogen-14 is 99.6%
This way of solving is limited to 2 isotopes only.
Done
Answer:
London dispersion forces
Explanation:
Intermolecular forces are the forces that facilitate interaction between solute and solvent molecules and thereby impact their solubility. These forces are broadly classified into four types arranged below from the strongest to the weakest:
1) Ionic > 2) Hydrogen bonding >3) Dipole-dipole >4) London dispersion
The hydrocarbons n-pentane and n--hexane are non-polar molecules. Therefore the only type of interaction that exists between them when forming a homogeneous solution are the weak london dispersion forces.