Answer:
pH = 10.75
Explanation:
To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]
Using the equation:
pH = 14 - pOH
We can find the pH of the solution.
The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M
pOH is
pOH = -log 5.6x10⁻⁴M
pOH = 3.25
pH = 14-pOH
<h3>pH = 10.75</h3>
Answer:
CH4 + 4Cl2 --> CCl4 + 4HCl
Explanation: Message me if you need a thorough explanation
The compound NaCI is an example of a salt. Salt is formed from a neutralization action of an acid and a base. From the type of reaction itself, we can say that the pH should be neutral or at pH 7.0. No matter what type of acid or base is used.
