Question

A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of

Answer 1

Mass of the water : 2.23 g

Furter explanation

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

mass of the water :

$\tt m=\dfrac{Q}{c.\Delta T}=\dfrac{140}{4.18\times 15}=2.23~g$