1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vfiekz [6]
3 years ago
12

5. The density of a substance is 3.4 X 10^3 g/mL. Mixing it with another substance increases the density by 1.5 X 10^1 times. Wh

at is the density of the mixture?​
Chemistry
2 answers:
kaheart [24]3 years ago
7 0

Answer:

the total density of the mixture = 3.415 x 10^3 g/mL

Explanation:

i got that correct on exam

JulijaS [17]3 years ago
5 0

Answer:

the total density of the mixture = 3.415 x 10^3 g/mL

Explanation:

given:

density of a substance is 3.4 x 10^3 g/mL

Mixing it with another substance increases the density by 1.5 x 10^1 times.

find:

What is the density of the mixture?​

-------------------------------------------------

let density (a) = 3.4 x 10^3 g/mL

density(b) = 1.5 x 10^1 g/mL

since there is no specific density provided for the mixture, we then add both to increase the density,

total density = density(a) + density(b)

total density = 3.4 x 10^3 g/mL + 1.5 x 10^1 g/mL

total density = 3.415 x 10^3 g/mL

therefore,

the total density of the mixture = 3.415 x 10^3 g/mL

You might be interested in
Write the balanced molecular and net ionic equations for the reaction between aluminum metal and silver nitrate. identify the ox
asambeis [7]

Well in this case, silver nitrate is reduced:

Ag<span>+  </span><span>+  </span>e<span>−  </span>→ Ag(s) ↓

 

Meanwhile, the aluminum is oxidized forming a positive ion:

Al(s<span>)  →  </span>Al<span>3+  </span><span>+  3</span>e−

 

To get the overall reaction,  we add the half equations so that the electrons are eliminated:

Al(s<span>)  +   3</span>Ag<span>+  </span><span>→  </span>Al<span>3+  </span><span>+  3</span>Ag(s)

 

And similarly:

Al(s<span>)  +  3</span>AgNO3(aq<span>)  →  </span>Al(NO3)3(aq<span>)  +  3</span>Ag(s<span>)</span>

4 0
2 years ago
Read 2 more answers
Use the following equation to answer the questions below.
notsponge [240]

Answer:

202

Explanation:

7 0
2 years ago
I took 100 micrograms of vitamin d yesterday (13yrs old) is it bad
Amanda [17]

Answer:

take 75 gm or it will be overdose

6 0
2 years ago
Would you weigh more or less on the moon than you do on Earth, and why?
VladimirAG [237]

Answer:You would weigh less on the moon because there is less gravity on the moon.

Explanation:

7 0
3 years ago
Read 2 more answers
A machine shop worker records the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density
forsale [732]

Answer:

Explanation:

So we take the given quotient:

ρ=176⋅g4⋅cm×4⋅cm×4⋅cm = 176⋅g64⋅cm3 = ??g⋅cm−3.

Would the cube float or sink in water? Why

6 0
3 years ago
Other questions:
  • If an atom has 35 protons in the nucleus, how many electrons will it have orbiting the nucleus?
    10·1 answer
  • When cellular respiration occurs, food energy is converted into chemical energy in the way of ATP, ______ and _____ are the prod
    11·2 answers
  • Characteristic of a chemical compound
    13·1 answer
  • Cuál será la masa molar de una sustancia donde 7 g equivalen a 0,25 mol
    6·1 answer
  • What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2
    11·1 answer
  •  why don't we ever see solid or liquid oxygen on earth?
    14·1 answer
  • When 1.04g of cyclopropane was burnt in excess oxygen in a bomb calorimeter, the temperature rose by 3.69K. The total heat capac
    13·1 answer
  • A rod made up of a single element is used to heat water using electricity. To which group does this element probably belong to?
    14·1 answer
  • HElp i am stuck and i am not sure
    13·1 answer
  • True/false... A molecule makes up a compound explain
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!