All categories

3 years ago

Match each compound with its appropriate pKa value.

Chemistry

1 answer:

zalisa [80]3 years ago

5 0

Answer:

Explanation:

a) 4-nitrobenzoic acid pKa= 3.41

benzoic acid pKa= 4.19

4-chlorobenzoic acid pKa= 3.98

b) benzoic acid pKa= 4.19

cyclohexanol pKa= 18.0

phenol pKa= 9.95

c) 4-Nitrobenzoic acid pKa= 3.41

4-nitrophenol pKa= 7.15

4-nitrophenylacetic acid pKa= 3.85

You might be interested in

How is dumping our waste different from dilution and dispersion?

ch4aika [34]

Dumping waste is different from dilution and dispersion. Dumping waste is directly disposing your waste and not regulating its effect to the environment. Dilution is done usually before waste water disposal, meaning adding water to the waste to minimize its concentration.

6 0

3 years ago

What is amplitude?

NISA [10]

What is amplitude?

<u />

<u>A: amplitude is the height of a wave </u>

B: amplitude is the number of complete waves that pass a point in a second

C: amplitude is the time it takes for one complete waves to a given point

D: amplitude is the distance between two crest or two troughs

6 0

3 years ago

Read 2 more answers

How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid acc

natulia [17]

The balanced equation for the reaction is as follows

Cu₂O + 2HCl ---> 2CuCl + H₂O

Molar ratio of Cu₂O to CuCl is 1:2

mass of Cu₂O reacted - 73.5 g

Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

According to the molar ratio,

when 1 mol of Cu₂O reacts then 2 mol of CuCl is formed

therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

number of CuCl moles formed - 1.02 mol

mass of CuCl formed - 1.02 mol x 99 g/mol = 101 g

mass of CuCl formed is 101 g

6 0

3 years ago

Analysis of a compound of sulfur, oxygen and fluorine showed that it is 31.42% S and 31.35% O, with F accounting for the remaind

Leya [2.2K]

Answer:

The molecular formula is SO2F2

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

The compound contains:

31.42 % S = 31.42 grams S

31.35 % O = 31.35 grams O

100 - 31.42 - 31.35 = 37.23 F

Molar mass of S = 32.065 g/mol

Molar mass F = 19.00 g/mol

Molar mass O = 16.00 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles S = 31.42 grams / 32.065 g/mol

Moles S = 0.9799 moles

Moles 0 = 31.35 grams / 16.00 g/mol

Moles 0 = 1.959 moles

Moles F = 37.23 grams / 19.00 g/mol

Moles F = 1.959 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.9799 / 0.9799 = 1

F: 1.959/ 0.9799 = 2

O : 1.959 / 0.9799 = 2

The empirical formula is SO2F2

This formula has a molecular mass of 102.06 g/mol

This means the empirical formula is also the molecular formula : SO2F2

3 0

3 years ago

How many molecules are in

diamong [38]

Answer:

3.6 × 10²⁴ molecules

Explanation:

Step 1: Given data

Moles of methane (n): 6.0 moles

Step 2: Calculate the number of molecules of methane in 6.0 moles of methane

In order to convert moles to molecules, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ molecules of methane in 1 mole of molecules of methane.

6.0 mol × 6.02 × 10²³ molecules/1 mol = 3.6 × 10²⁴ molecules

6 0

3 years ago