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Olenka [21]
3 years ago
9

How many moles of O2 are needed to react with 2.55 mol of C2H2?

Chemistry
1 answer:
Lelechka [254]3 years ago
3 0

Answer: 6.38 moles of O_2 are needed to react with 2.55 mol of C_2H_2

Explanation:

The balanced chemical reaction for the combustion of ethyne is:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

According to stoichiometry:

2 moles of C_2H_2 require = 5 moles of O_2

Thus 2.55 mol of C_2H_2 require = \frac{5}{2}\times 2.55=6.38 moles of O_2

Thus 6.38 moles of O_2 are needed to react with 2.55 mol of C_2H_2

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valina [46]

Answer:

MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

Explanation:

Half reaction:MnCO_{3}\rightarrow MnO_{2}

(1)CO_{3} balance: MnCO_{3}\rightarrow MnO_{2}+HCO_{3}^{-}

(2)H and O balance in acidic medium:MnCO_{3}+2H_{2}O\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

(3) charge balance:MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

Hence balanced half-reaction:MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}

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3 years ago
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What would happen to the volume of a sample of gas if the temperature was decreased at the same time the pressure was increased?
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Answer:

It would decrease

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3 years ago
What is the mass of 2.16 moles of sulfur dioxide (SO2)?
Luda [366]
<h3>Answer:</h3>

138 g SO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 2.16 moles SO₂

[Solve] grams (mass) SO₂

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 2.16 \ mol \ SO_2(\frac{64.07 \ g \ SO_2}{1 \ mol \ SO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 138.391 \ g \ SO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

138.391 g SO₂ ≈ 138 g SO₂

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